php - 如何在PHP中分别求和二维数组的值

问题说明：将二维数组的值相加，分别保存。
JSON字符串：

{
    "user_name": "USER1",
    "selected_date": "07/27/2015",
    "selected_project": "PROJECT1",
    "tasks": [{
        "task_name": " Task-1",
        "work_hours": [{
            "Monday": " 2"
        },
        {
            "Tuesday": " 1"
        },
        {
            "Wednesday": " 4"
        },
        {
            "Thursday": " 0"
        },
        {
            "Friday": " 0"
        },
        {
            "Saturday": " 0"
        },
        {
            "Sunday": " 0"
        }]
    },
    {
        "task_name": " Task-2",
        "work_hours": [{
            "Monday": " 5"
        },
        {
            "Tuesday": " 1"
        },
        {
            "Wednesday": " 5"
        },
        {
            "Thursday": " 0"
        },
        {
            "Friday": " 0"
        },
        {
            "Saturday": " 0"
        },
        {
            "Sunday": " 0"
        }]
    }]
}

代码

.....
$str_json = file_get_contents('php://input');
$response = json_decode($str_json, true); // decoding received JSON to array
decoded = json_decode($response, true);
$task_counter = count($decoded['tasks']);
$hour_counter = count($decoded['tasks'][0]['work_hours']);
$_tasks = array();
$_hours = array();
$_hours[] = array();

按要求提取工时：

for ( $var1 = 0; $var1 <= $task_counter; $var1++)
{
  $_hours[$var1][] = $decoded['tasks'][$var1]['work_hours'][0]['Monday'];
  $_hours[$var1][] = $decoded['tasks'][$var1]['work_hours'][1]['Tuesday'];
  $_hours[$var1][] = $decoded['tasks'][$var1]['work_hours'][2]['Wednesday'];
  $_hours[$var1][] = $decoded['tasks'][$var1]['work_hours'][3]['Thursday'];
  $_hours[$var1][] = $decoded['tasks'][$var1]['work_hours'][4]['Friday'];
  $_hours[$var1][] = $decoded['tasks'][$var1]['work_hours'][5]['Saturday'];
  $_hours[$var1][] = $decoded['tasks'][$var1]['work_hours'][6]['Sunday'];
}

for($var = 0; $var <= $task_counter; $var++)
{
    echo "|";
    for ($var1 = 0; $var1 <= 7; $var1++)
  {
     echo $_hours[$var][$var1];
  }
}

$_totalArray = array();
for ( $i=0 ; $i<=7; $i++)
{
    foreach($_hours as $num => $values)
    {

       $_totalArray[$i] += $values[$i];
  }
 }
echo "<br>Task-1:$_totalArray[0]";
echo "Task-2:$_totalArray[1]";


....

预期结果：特定任务的工作时间总和。
例子：
任务1：7
任务2：11
不幸的是我的逻辑出了问题。
我们将非常感谢您的帮助。

最佳答案

这可以做得简单得多：

$decoded = json_decode($str_json, true); // decoding received JSON to array

foreach ($decoded['tasks'] as $task) {
    $total = 0;
    foreach ($task['work_hours'] as $day) {
        foreach ($day as $key=>$value) {
            $total += $value;
        }
    }
    echo $task['task_name'] .': ' . $total .'<br/>';
}

输出
任务1：7
任务2：11

关于php - 如何在PHP中分别求和二维数组的值，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/31166941/