javascript - 我不明白我的If陈述如何被视为正确

我正在做一个石头剪刀布游戏，希望将验证添加到提示方法中，以便如果用户键入的单词不是“石头”，“纸张”或“剪刀”，那么我们将再次提示。

我似乎无法理解为什么下面的代码不起作用，即使我键入“ rock”，它也会提示我再次输入。

for (i = 0; i < 5; i++) {
        let valid = false;
        let askPlayer = prompt("Rock, Paper or Scissor?");
        while(!valid) {
            if (askPlayer !== "rock" || askPlayer !== "paper" || askPlayer !== "scissor" || askPlayer !== "Rock" || askPlayer !== "Paper" || askPlayer !== "Scissor") {
                askPlayer = prompt("Enter again. You seem to have entered an invalid value");

            }
            else { valid = true; }
        }
        play(askPlayer, computerPlay());
    }

最佳答案

我认为您可能会混淆肯定派和否定派。您的条件是：“如果玩家提供的值与上述任何一项都不匹配，则再次询问”

更人性化的条件是：

var valid_responses = ["rock","paper","scissors"];
if (valid_responses.includes(askPlayer.toLowerCase())){
  valid = true;
} else {
  askPlayer = prompt("Enter again. You seem to have entered an invalid value");
}