我正在尝试使用JS开发一个简单的BlackJack游戏。这是我的一些代码:
function card(suit, face) {
this.suit = suit;
this.face = face;
switch (face) {
case "A":
this.faceValue = 11;
break;
case "J":
case "Q":
case "K":
this.faceValue = 10;
break;
default:
this.faceValue = parseInt(face);
break;
}
};
const player = {
cards: [],
handValue: 0
}
const dealOneCardToPlayer = () => {
tempCard = deck.cards.splice(0, 1);
player.cards.push(tempCard);
player.handValue = countHandValue(player.cards);
}
我受困于countHandValue方法,无法获得玩家对象的Cards的faceValue。我尝试了几种类型的for循环,但仍然没有成功。一旦获得faceValue,就可以将其汇总并分配给handValue属性。
const countHandValue = (cardsOnHand) => {
for (const key of cardsOnHand) {
console.log(key.faceValue);
}
for (const key in cardsOnHand) {
console.log(key.faceValue);
}
}
[代码编辑]我搜索并找到了此代码,可以检索我的faceValue属性,但我相信还有很多额外的代码:
const countHandValue = (cardsOnHand) => {
let sum = 0;
for (var key in cardsOnHand) {
var arr = cardsOnHand[key];
for (var i = 0; i < arr.length; i++) {
var obj = arr[i];
for (var prop in obj) {
if (prop === "faceValue") {
console.log(prop + " = " + obj[prop]);
sum = sum + obj[prop];
}
}
}
}
return sum;
}
最佳答案
请确保A
的得分为1或11。该程序向您展示了如何处理-
const add = (x = 0, y = 0) =>
x + y
const sum = (a = []) =>
a .reduce (add, 0)
const scoreCard = (face = "") =>
face === "A"
? [ 11, 1 ]
: (face === "K") || (face === "Q") || (face === "J")
? [ 10 ]
: [ Number (face) ]
const allScores = ([ face = "", ...more ]) =>
face === ""
? [ scoreCard (face) ]
: allScores (more)
.flatMap
( hand =>
scoreCard (face) .map (v => [ v, ...hand ])
)
const scoreHand = (...hand) =>
{ const [ best = "Bust" ] =
allScores (hand)
.map (sum)
.filter (score => score <= 21)
if (best === 21)
return "Blackjack!"
else
return String (best)
}
console .log
( scoreHand ("A", "K") // Blackjack!
, scoreHand ("A", "A", "K") // 12
, scoreHand ("A", "A", "K", "7") // 19
, scoreHand ("J", "4", "K") // Bust
, scoreHand ("A", "A", "A", "A", "K", "7") // Blackjack!
)