java - 将JSON数组发布到Spring Boot 2 JPA中

我想这样发布：

[{
        "employeeid": "1111",
        "employeename": "YOA"

},
{
        "employeeid": "2222",
        "employeename": "OYA"
}]

我的控制器是这样的：

@PostMapping("/api/employee/save")
public Employee createEmployee(@Valid @RequestBody List<Employee> employee) {
        return employeeService.save(employee);
}

型号：

@Entity
@Table(name="EMPLOYEE")
public class Employee implements Serializable{
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
@Column(name = "ID")
int id;
@Column(name = "EMP_ID")
int employeeid;
@Column(name = "EMPLOYEE_NAME")
String employeename;

//GETTER AND SETTER
}

当我发布数据时，出现的错误如下：

{
    "timestamp": "2018-07-13T03:36:25.898+0000",
    "status": 500,
    "error": "Internal Server Error",
    "message": "Invalid property 'id' of bean class [java.util.ArrayList]: Could not find field for property during fallback access!",
    "path": "/api/employee/save"
}

服务内容：

public interface employeeService{

    Employee save(List<Employee> employee);

}

服务展示次数：

@Service("employeeService")
public class EmployeeServiceImpl implements EmployeeService {

    @Autowired
    EmployeeRepository employeeRepository;

    @Override
    public Employee save(List<Employee> employee) {
     return employeeRepository.save(employee);
}

}

仓库：

public interface EmployeeRepository extends Repository <Employee, Long>
    Employee save(List<Employee> employee);
}

错误描述是这样的：
Bean类[java.util.ArrayList]的无效属性'id'：在后备访问期间找不到属性的字段！

当使用saveAll（）时，我得到错误消息：找不到类型为Employee的属性saveAll

有谁可以帮助我吗？
我已经修改了我的问题。

问候，
我

最佳答案

问题在这条线

public Employee createEmployee(@Valid @RequestBody List<Employee> employee) {
        return employeeService.save(employee);  //  Problem
}

employeeService.save在您的情况下只能采用一个实体对象Employee

有2种方法

1。

public Boolean createEmployee(@Valid @RequestBody List<Employee> lstEmployee) {
    try{
        for(Employee emp : lstEmployee){
            employeeService.save(employee);
        }
        return true;
    }catch(Exception e){}
    return false;
}

2。

使用saveAll代替

public Employee createEmployee(@Valid @RequestBody List<Employee> employee) {
        return employeeService.saveAll(employee);
}

编辑1：

添加服务类后，您似乎正在手动实现，因此

选项1：

我建议您直接在控制器类中使用EmployeeRepository。
就像通过手动覆盖那里的方法，您实际上并没有
享受使用存储库的好处

@Autowired
EmployeeRepository employeeRepository;

@PostMapping("/api/employee/save")
public Employee createEmployee(@Valid @RequestBody List<Employee> lstEmployee) {
        return employeeRepository.saveAll(lstEmployee);
}

选项2：

从长远来看，像这样更改您的实现。对象可能有一些错误，但应该可以给您一个提示

public interface employeeService{

    Employee save(Employee employee);

    public <S extends User> List<S> saveAll(Iterable<S> entites);



}

@Service("employeeService")
public class EmployeeServiceImpl implements EmployeeService {

    @Autowired
    EmployeeRepository employeeRepository;

    @Override
    public Employee save(Employee employee) {
        return employeeRepository.save(employee);
    }

   @Override
    public List<Employee> saveAll(List<Employee> employee) {
        return employeeRepository.saveAll(employee);
    }

}