$query = mysql_query("SELECT Name from lottery");
// Make All Lotteries Into An Array
$queryarray = mysql_fetch_array($query);
// For Each Lottery, Store the Name of It in $lottery
foreach ($queryarray as $lottery) {
// Select IDs of Tickets in Current Selected Lottery ($lottery)
$ticketquery = mysql_query("SELECT id FROM tickets WHERE lottery='$lottery'");
// Create an Array from the IDS
$ticketarray = mysql_fetch_assoc($ticketquery);
// Select A Random ID, This Is Our Winner Ticket
$winner = $ticketarray[array_rand($ticketarray)];
}
但是,当我运行此命令时,出现以下错误:“警告:array_rand()[function.array-rand]:第一个参数必须是第25行的public_html / php / lotterypick.php中的数组”
我试图用
mysql_fetch_assoc
替换mysql_fetch_array
,但也没有太大帮助。只是给了我同样的错误。有任何想法吗?谢谢。第25行:
$winner = $ticketarray[array_rand($ticketarray)];
最佳答案
将代码编写为:
while($lottery = mysql_fetch_array($query)){...}
会解决问题。
关于php - 使用mysql_fetch_assoc获取数组,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/29321563/