我有一个这样的杂烩:
{
"category" => ["sport", "gaming", "other"],
"duration" => 312,
"locations" => {
"688CQQ" => {"country" => "France", "state" => "Rhône-Alpes"},
"aUZCAQ" => {"country" => "France", "state" => "Île de France"}
}
}
如果值是散列,我希望通过展平一个值来将其还原为散列而不嵌套。在最终值中,我应该只有整数、字符串或数组,如下所示:
{
"category" => ["sport", "gaming", "other"],
"duration" => 312,
"locations_688CQQ_country" => "France",
"locations_688CQQ_state" => "Rhône-Alpes",
"locations_aUZCAQ_country" => "France",
"locations_aUZCAQ_state" => "Île de France"
}
我想要一个可以与任何级别的嵌套一起工作的函数。我怎么能用鲁比呢?
最佳答案
这里有一个递归方法,其中h
是您的散列。
def flat_hash(h)
h.reduce({}) do |a, (k,v)|
tmp = v.is_a?(Hash) ? flat_hash(v).map { |k2,v2| ["#{k}_#{k2}",v2]}.to_h : { k => v }
a.merge(tmp)
end
end
关于ruby - 拼合哈希并连接 key ,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/34270973/