我从他们的示例项目中获得了这段代码。
NSString *message = @"Hello man!";
NSMutableDictionary *payload = [NSMutableDictionary dictionary];
NSMutableDictionary *aps = [NSMutableDictionary dictionary];
[aps setObject:@"default" forKey:QBMPushMessageSoundKey];
[aps setObject:message forKey:QBMPushMessageAlertKey];
[payload setObject:aps forKey:QBMPushMessageApsKey];
QBMPushMessage *pushMessage = [[QBMPushMessage alloc] initWithPayload:payload];
[QBRequest sendPush:pushMessage toUsers:@"292,300,1395" successBlock:^(QBResponse *response, QBMEvent *event) {
// Successful response with event
} errorBlock:^(QBError *error) {
// Handle error
}];
我将其转换为
let mesage = "Hello man!"
var payload = [String:String]()
var aps = [String:String]()
aps[QBMPushMessageSoundKey] = "default"
aps[QBMPushMessageAlertKey] = mesage
payload[QBMPushMessageApsKey] = aps //Cannot assign value of type '[String : String]' to type 'String?'
let message = QBMPushMessage(payload: payload)
最佳答案
let pushMessage = QBMPushMessage()
pushMessage.payloadDict = ["aps":aps]
为我工作:)
关于ios - 如何在Swift 4.0中使用Quickblox以编程方式发送推送通知?,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/47109892/