python - Python:urlopen-如果发生任何错误，则跳过条目

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想改进这个问题吗Update the question所以堆栈溢出的值小于aa>
我想知道，如果在访问网站时出现任何错误，urlopen是否有某种“全部捕获”代码会跳过for循环中的整个条目。

最佳答案

您可以使用try/except块捕获异常：

# Python 3 example
from urllib.error import URLError, HTTPError
from urllib.request import urlopen

for entry in entries:
    try:
         data = urlopen(...)
    except URLError, HTTPError:
         print("Something bad happened")
    else:
         # Process data get from the URL opened
         # If an exception has been catch, you won't
         # enter in this else block