我想对具有某些参数(名称,电子邮件,密码等)的用户注册进行简单的HTTPRequest到php脚本。我已经尝试了许多来自Internet的教程,但对我没有任何帮助。 HTTP POST抛出NullpointerException。在后端也显示null。

我的代码是:

        //JSON Node Names

        private static final String TAG_ID = "status";
        private static final String TAG_NAME = "code";
        private static final String TAG_EMAIL = "message";
        //POST data
        HttpClient httpclient = new DefaultHttpClient();
                HttpPost httppost = new HttpPost(url);

                // Add your data
                List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(5);
                nameValuePairs.add(new BasicNameValuePair("user_name", "Steve"));
                nameValuePairs.add(new BasicNameValuePair("user_email", "jjdnjdn"));
                nameValuePairs.add(new BasicNameValuePair("user_password", "dcds"));
                nameValuePairs.add(new BasicNameValuePair("user_phone_number", "2343"));
                nameValuePairs.add(new BasicNameValuePair("club_member_id", "24"));
                httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
     //For receiving response
// Creating new JSON Parser
            JSONParser jParser = new JSONParser();

            // Getting JSON from URL
            JSONObject json = jParser.getJSONFromUrl(url);
            Log.e("Data", String.valueOf(json));
            try {
     String id = json.getString(TAG_ID);
                String name = json.getString(TAG_NAME);
                String email = json.getString(TAG_EMAIL);
                Toast.makeText(getContext(), id , Toast.LENGTH_SHORT).show();
                Toast.makeText(getContext(), name , Toast.LENGTH_SHORT).show();
                Toast.makeText(getContext(), email , Toast.LENGTH_SHORT).show();
     } catch (JSONException e) {
                e.printStackTrace();
            }

        }


Logcat错误

      E/JSON Parser: Error parsing data org.json.JSONException: Value null of type org.json.JSONObject$1 cannot be converted to JSONObject
      E/Data: null
java.lang.NullPointerException: Attempt to invoke virtual method 'java.lang.String org.json.JSONObject.getString(java.lang.String)' on a null object reference


PHP代码

<?php
  print_r($_POST);
?>


获取空数组。

最佳答案

jParser.getJSONFromUrl(url)似乎是GET而不是POST(而且无论如何您都没有使用httppost或从jParser引用了它,因此它不能确定是否发布数据。

在ephp中,您可能还需要在回显json主体之前发送正确的Content-type标头,因为jParser可能依赖于它。

08-17 22:26