当使用泛型时,rxswifttoArray
对我不起作用:
struct SaveModelsCommand<M> where M:Model {
let models:[M]
func create() -> Observable<[M]> {
let cloudKitRecords:[CKRecord] = models.map({
// convert models to CKRecords
...
})
return SaveRecordsCommand(cloudKitRecords)
.createObservable()
.flatMap({ savedRecords in
// convert array to multiple emissions so we can iterate it
return Observable.from(savedRecords)
})
.flatMap({ (record:CKRecord) -> M in
// convert CKRecord back to a model (aka M)
... create model (e.g. Member) ...
return model
})
// convert back to a single emission (array)
.toArray() // <<<<< ERROR
}
}
错误如下:
无法将“observate”类型(也称为“observate>”)的返回表达式转换为“observate”类型(也称为“observate>”)
我在返回类型中看到的唯一区别是
M.E
vsM
。有什么想法吗?
最佳答案
flatMap
期望闭包返回一个Observable<M>
,而不仅仅是一个普通的M
:
.flatMap({ (record:CKRecord) -> Observable<M> in
// convert CKRecord back to a model (aka M)
//... create model (e.g. Member) ...
return Observable.just(model)
})
或者,您可以使用
map
并返回M
:.map({ (record:CKRecord) -> M in
// convert CKRecord back to a model (aka M)
//... create model (e.g. Member) ...
return model
})