我正在尝试获取SceneKit中触摸位置的条件。我触摸SpriteKit对象,并编写该代码以获取SKnode对象:

class GameViewController: UIViewController , SCNSceneRendererDelegate {

var overlay: SKScene!

...

override public func touchesEnded(_ touches: Set<UITouch>, with event: UIEvent!) {

   for touch: AnyObject in touches {
        let location: CGPoint  = touch.location(in: overlay)
        let touchedNode: SKNode = overlay.nodes(at: location

        if(touchedNode.name == "WalkAnimationButton") {

            self.tap()
        }
        else if(touchedNode.name == "CameraButton") {

            sceneView.allowsCameraControl = true
        }
        else if(touchedNode.name == "WrenchButton") {

            sceneView.showsStatistics = true
        }
        else if(touchedNode.name == "CharacterButton") {
            if(currentCharacter < characterPaths.count-1) {
                currentCharacter = currentCharacter+1
            }
            else{
                currentCharacter = 0
            }
        }

    }

    self.setCharacterFromModelWithName(name: characterPaths[currentCharacter] as! NSString)
}

Xcode编写了我从未遇到过的错误:
无法将类型“[SKNode]”的值转换为指定的类型“SKNode”

最佳答案

要调用被触摸的节点,我们应该使用该代码:

let touchedNode: SKNode = overlay.atPoint(location)

因为我们调用SpriteKit对象的名称,它用作SKNode类的成员。

关于compiler-errors - SpriteKit Swift3接触了SKNode,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/43305756/

10-13 04:01