我有一个不可复制的X类型,我想公开一个创建它们的list的函数:

#include <boost/python.hpp>

namespace py = boost::python;

struct X {
    X(int i) : i(i) { }
    X(const X& ) = delete;
    X& operator=(X const&) = delete;

    int i;
    friend std::ostream& operator<<(std::ostream& os, X const& x) {
        return os << "X(" << x.i << ")";
    }
};

py::list get_xs(int n) {
    py::list xs;
    for (int i = 0; i < n; ++i) {
        xs.append(X{i});
    }
    return xs;
}

BOOST_PYTHON_MODULE(Foo)
{
    py::class_<X, boost::noncopyable>("X", py::init<int>())
        .def(str(py::self))
        .def(repr(py::self))
    ;

    py::def("get_xs", get_xs);
}

这可以很好地编译,但是当我尝试使用它时,却使我感到恐惧:
>>> import Foo
>>> Foo.get_xs(10)
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
TypeError: No to_python (by-value) converter found for C++ type: X

该错误实际上是什么意思?我如何解决它?

最佳答案

noncopyable似乎是问题所在。如果X是可复制的,那么一切都很好。

如果X必须为noncopyable,则可以使用boost::shared_ptr:

py::list get_xs(int n) {
    py::list xs;
    for (int i = 0; i < n; ++i) {
        xs.append(boost::shared_ptr<X>(new X(i)));
    }
    return xs;
}

....

BOOST_PYTHON_MODULE(Foo)
{
    py::class_<X, boost::shared_ptr<X>, boost::noncopyable>("X", py::init<int>())
    ...
    ...

    py::register_ptr_to_python<boost::shared_ptr<X>>();
}

08-16 09:27