我正在尝试使用OpenCV tutorial on image template matching跟随javacpp-presets。
我想丢掉得分太低的比赛,但minMaxLoc
似乎不返回minVal
和maxVal
。
import org.bytedeco.javacpp.DoublePointer;
import org.bytedeco.javacpp.opencv_core.Mat;
import org.bytedeco.javacpp.opencv_core.Point;
import static org.bytedeco.javacpp.opencv_core.CV_32FC1;
import static org.bytedeco.javacpp.opencv_core.NORM_MINMAX;
import static org.bytedeco.javacpp.opencv_core.minMaxLoc;
import static org.bytedeco.javacpp.opencv_core.normalize;
import static org.bytedeco.javacpp.opencv_imgcodecs.IMREAD_COLOR;
import static org.bytedeco.javacpp.opencv_imgcodecs.imread;
import static org.bytedeco.javacpp.opencv_imgproc.TM_CCOEFF_NORMED;
import static org.bytedeco.javacpp.opencv_imgproc.matchTemplate;
public class MatchTemp {
public static void match(String img, String temp) {
Mat image = imread(img, IMREAD_COLOR);
Mat template = imread(temp, IMREAD_COLOR);
int resultRows = image.rows() - template.rows() + 1;
int resultCols = image.cols() - template.cols() + 1;
Mat result = new Mat(resultRows, resultCols, CV_32FC1);
matchTemplate(image, template, result, TM_CCOEFF_NORMED);
Mat normalizedResult = new Mat();
normalize(result, normalizedResult, 0, 1, NORM_MINMAX, -1, new Mat());
DoublePointer maxVal = new DoublePointer();
DoublePointer minVal = new DoublePointer();
Point minLoc = new Point();
Point maxLoc = new Point();
minMaxLoc(normalizedResult, minVal, maxVal, minLoc, maxLoc, null);
System.out.println("min: "+minLoc.x()+", "+minLoc.y());
System.out.println("max: "+maxLoc.x()+", "+maxLoc.y());
minVal.get(); // this throws exception
maxVal.get(); // this throws exception
}
}
异常(exception)是:
Exception in thread "main" java.lang.NullPointerException: This pointer address is NULL.
at org.bytedeco.javacpp.DoublePointer.get(Native Method)
at org.bytedeco.javacpp.DoublePointer.get(DoublePointer.java:101)
...
我究竟做错了什么?我如何获得分数?我是否需要手动检查
Mat
的内容? 最佳答案
该错误告诉您它正在尝试访问Null引用。阅读DoublePointer constructor的文档,它告诉您看看Pointer.Pointer(),它基本上告诉您以下内容:
这意味着它只是一个类似于C++的指针:
double *p;
它不指向任何double,但是文档告诉您DoublePointer还有另一个构造函数
public DoublePointer(long size)
表示它分配了这个大小的数组。如果size等于1,则相当于在C++中等于:
double p[1];
或基本上
double *p = new double;
我从未使用过JavaCpp,因此,如果我错过了一些事情,请发表评论。