是否有任何资源可以测试jQuery脚本/扩展名/插件/任何版本兼容性问题?
最佳答案
刚刚写了一个小jQuery插件来解决版本兼容性问题...随时对其进行改进。
(function($) {
/**
* Used for version test cases.
*
* @param {string} left A string containing the version that will become
* the left hand operand.
* @param {string} oper The comparison operator to test against. By
* default, the "==" operator will be used.
* @param {string} right A string containing the version that will
* become the right hand operand. By default, the current jQuery
* version will be used.
*
* @return {boolean} Returns the evaluation of the expression, either
* true or false.
*/
$.isVersion = function(left, oper, right) {
if (left) {
var pre = /pre/i,
replace = /[^\d]+/g,
oper = oper || "==",
right = right || $().jquery,
l = left.replace(replace, ''),
r = right.replace(replace, ''),
l_len = l.length, r_len = r.length,
l_pre = pre.test(left), r_pre = pre.test(right);
l = (r_len > l_len ? parseInt(l) * ((r_len - l_len) * 10) : parseInt(l));
r = (l_len > r_len ? parseInt(r) * ((l_len - r_len) * 10) : parseInt(r));
switch(oper) {
case "==": {
return (true === (l == r && (l_pre == r_pre)));
}
case ">=": {
return (true === (l >= r && (!l_pre || l_pre == r_pre)));
}
case "<=": {
return (true === (l <= r && (!r_pre || r_pre == l_pre)));
}
case ">": {
return (true === (l > r || (l == r && r_pre)));
}
case "<": {
return (true === (l < r || (l == r && l_pre)));
}
}
}
return false;
}
})(jQuery);
可以这样使用:
$.isVersion("1.4.2"); // returns true, if $().jquery == "1.4.2"
$.isVersion("1.3.2", ">"); // returns true if $().jquery > "1.3.2"
$.isVersion("1.3", ">", "1.2.6"); // returns true
$.isVersion("1.3.2", "<", "1.3.1"); // returns false
$.isVersion("1.4.0", ">=", "1.3.2"); // returns true
$.isVersion("1.4.1", "<=", "1.4.1"); // returns true
还支持预发行版(发行版的权重比预发行版重,因此1.4.0pre
$.isVersion("1.4.2", "<=", "1.4.2pre"); // returns false