python - 如何获得键值最低的字典

这是我的字典架构。

f = { 'client_id': {'client_name': [{'transaction_date': date_time,
                                     'transaction_amount': value_in_dollar}]
                   }
    }

如何获得具有最低transaction_amount的字典。

输入示例：

f = { 905220: {'Steven Jhon': [{'transaction_date': '2016-05-07 00:00:00+00',
                              'transaction_amount': 1198},
                             {'transaction_date': '2016-05-08 00:00:00+00',
                              'transaction_amount': 4889}]
              },
      905221: {'Chris Chris': [{'transaction_date': '2016-05-01 00:00:00+00',
                                  'transaction_amount': 50},
                                 {'transaction_date': '2016-05-02 00:00:00+00',
                                  'transaction_amount': 100},
                                 {'transaction_date': '2016-05-03 00:00:00+00',
                                  'transaction_amount': 10}]
               }
    }

期望的输出：

f = { 905220: {'Steven Jhon': [{'transaction_date': '2016-05-07 00:00:00+00',
                              'transaction_amount': 1198}]
              },
      905221: {'Chris Chris': [{'transaction_date': '2016-05-03 00:00:00+00',
                                  'transaction_amount': 10}]
               }
    }

最佳答案

您可以使用大的dict理解力，或类似这样的辅助函数：

def get_min_by_value(x):
  if isinstance(x, dict):
    return {k: get_min_by_value(v) for k, v in x.items()}
  elif isinstance(x, list):
    return [min(x, key=lambda d: d['transaction_amount'])]

out = get_min_by_value(f)

关于python - 如何获得键值最低的字典，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/37792901/