我正试着从TripAdvisor中搜集某个酒店的数据。
TripAdvisor中酒店的URL是
https://www.tripadvisor.com/Hotel_Review-g39143-d92240-Reviews-Hawthorn_Suites_by_Wyndham_Wichita_East-Wichita_Kansas.html
页面分隔符出现在“d92240评论”后面，键“-or5-”是5的倍数，页面返回5个评论。
如
https://www.tripadvisor.com/Hotel_Review-g39143-d92240-Reviews-or5-Hawthorn_Suites_by_Wyndham_Wichita_East-Wichita_Kansas.html
https://www.tripadvisor.com/Hotel_Review-g39143-d92240-Reviews-or10-Hawthorn_Suites_by_Wyndham_Wichita_East-Wichita_Kansas.html
对于url以“&start=（结果数）”结尾的页面，我可以创建for循环来返回每个页面
for i in range(0,200,5):
url = http://blahblahblah&start= + str(i)
但是我不知道如何使用我的tripadvisor url。
最佳答案
干得好：
initial='https://www.tripadvisor.com/Hotel_Review-g39143-d92240-Reviews-Hawthorn_Suites_by_Wyndham_Wichita_East-Wichita_Kansas.html'
url_part1='https://www.tripadvisor.com/Hotel_Review-g39143-d92240-Reviews-or'
url_part2='-Hawthorn_Suites_by_Wyndham_Wichita_East-Wichita_Kansas.html'
print (initial)
for index in range (5,200, 5):
print(url_part1+str(index)+url_part2)