我正在尝试使用Rainbow Tables编写程序来哈希和破解长度为四的密码。哈希值的算法为:ℎ𝑎𝑠ℎ𝑉𝑎𝑙𝑢𝑒=(163 ∗𝑝𝑜𝑠𝑡𝑖𝑜𝑛0)+(162 ∗𝑝𝑜𝑠𝑡𝑖𝑜𝑛1 +(161 ∗𝑝𝑜𝑠𝑡𝑖𝑜𝑛2)+(160 ∗𝑎𝑡3)。

我需要帮助找出我在计算方法上做错了什么。在代码之前有注释,指出如果需要这样做将有助于解决问题,该怎么做。

public void compute() {
    //TODO:  Add code to compute all possible 4-letter passwords - store in rainbow
    // Begin your possible passwords with aaaa and end with zzzz
    // Use hashCode(pwd) % 29 to determine the key (index) of where this element should be added to rainbow's ArrayList of ArrayLists
    // You will need to cast as int, such as key = (int) hashCode(pwd)%29  - key is the index of where to add this element in the rainbow ArrayList of ArrayLists
    if(password.length() != passwordLength){
        throw new InvalidPasswordException();
    }
    while(password.startsWith("aaaa") && password.endsWith("zzzz")){
        key = (int) (hashCode(password)%29);
        rainbow.add(key, password);
    }
}


请让我知道是否需要更多信息。

编辑:这是完整的代码,因此可以看到所有其他方法(还不是全部完成)

import java.util.*;
public class HashMap implements HashMapADT{
private String password;
private Long hash;
private int key;
private final int passwordLength = 4;
ArrayList<ArrayList<PasswordMap>> rainbow;

public HashMap() {
    password = "";
    hash = -1L;
    key = -1;
    initializeHashMap();
}
public HashMap(String str) {
    password = str;
    hash = hashCode(str);
    key = (int)(hash % 29);
    initializeHashMap();
}

private void initializeHashMap() {
    //Initialize an ArrayList of 29 elements - when dividing by 29 only remainders 0 - 28 are possible
    rainbow = new ArrayList<>();
    for(int i = 0; i < 29; i++) {
        rainbow.add(new ArrayList<PasswordMap>());
    }
    compute();
}

public Long hashCode(String str) throws InvalidPasswordException{
    this.hash = 0L;

    //TODO:  Calculate hashCode using hashing function based on powers of 29

    return 0L;  // temp - delete once hashCode method is implemented.
}

public void compute() {
    //TODO:  Add code to compute all possible 4-letter passwords - store in rainbow
    // Begin your possible passwords with aaaa and end with zzzz
    // Use hashCode(pwd) % 29 to determine the key (index) of where this element should be added to rainbow's ArrayList of ArrayLists
    // You will need to cast as int, such as key = (int) hashCode(pwd)%29  - key is the index of where to add this element in the rainbow ArrayList of ArrayLists
    if(password.length() != passwordLength){
        throw new InvalidPasswordException();
    }
    while(password.startsWith("aaaa") && password.endsWith("zzzz")){
        key = (int) (hashCode(password)%29);
        rainbow.add(key, password);
    }
}
public Long hash(String pwd) {
    //TODO:  Return the hashcode for a given password
    // First, hash the password: int key = (int)(hashCode(pwd) % 29);
    // Use this key to determine which element in the rainbow table you should be traversing to find the hash code
    // Recall rainbow is an ArrayList of ArrayLists!!
    key = (int)(hashCode(pwd)%29);

    return 0L;  // temp - delete once hash method is implemented.
}

public String hack(Long pwdHash) {
    String pwd="";
    //TODO:  Given a hashed password, pwdHash, determine the password
    // When identifying a correct hashed password, you will need to look at a difference RATHER THAN ==
    // That is,
    //if (Math.abs(pwdHash - rainbow.get(key).get(i).getHash())<.001)  -  you've found your password!!
    // Note:  key is the location of the rainbow list you should be traversing:  key = (int)((pwdHash) % 29);


    return pwd;
}

@Override
public String toString() {
    return password + ": " + hash;
}


}

最佳答案

这里的问题是您的while循环。

while(f())表示“只要f()返回true,请继续这样做”。

您已经说过“只要password以“ aaaa”开头并且password以“ zzzz”结尾,就继续这样做。

我们看不到您初始化password,但是如果它是如上所述的四个字符的字符串,则不可能以“ aaaa”开头和以“ zzzz”结尾,因此while循环的块将永远不会执行。

如果password"aaaazzzz",那么条件成立,那么,由于您从不修改password的值,因此while循环将永远重复。

您可能想要类似:

for(int i=0;; i++) {
    String password = createPassword(i);
    rainbow.add(password, hash(password));
}


...并编写方法createPassword(),使createPassword(0)返回“ aaaa”,createPassword(1)返回“ aaab”,createPassword(26)返回“ aaba”,依此类推。

10-08 09:07