我正在尝试使用Rainbow Tables编写程序来哈希和破解长度为四的密码。哈希值的算法为:ℎ𝑎𝑠ℎ𝑉𝑎𝑙𝑢𝑒=(163 ∗𝑝𝑜𝑠𝑡𝑖𝑜𝑛0)+(162 ∗𝑝𝑜𝑠𝑡𝑖𝑜𝑛1 +(161 ∗𝑝𝑜𝑠𝑡𝑖𝑜𝑛2)+(160 ∗𝑎𝑡3)。
我需要帮助找出我在计算方法上做错了什么。在代码之前有注释,指出如果需要这样做将有助于解决问题,该怎么做。
public void compute() {
//TODO: Add code to compute all possible 4-letter passwords - store in rainbow
// Begin your possible passwords with aaaa and end with zzzz
// Use hashCode(pwd) % 29 to determine the key (index) of where this element should be added to rainbow's ArrayList of ArrayLists
// You will need to cast as int, such as key = (int) hashCode(pwd)%29 - key is the index of where to add this element in the rainbow ArrayList of ArrayLists
if(password.length() != passwordLength){
throw new InvalidPasswordException();
}
while(password.startsWith("aaaa") && password.endsWith("zzzz")){
key = (int) (hashCode(password)%29);
rainbow.add(key, password);
}
}
请让我知道是否需要更多信息。
编辑:这是完整的代码,因此可以看到所有其他方法(还不是全部完成)
import java.util.*;
public class HashMap implements HashMapADT{
private String password;
private Long hash;
private int key;
private final int passwordLength = 4;
ArrayList<ArrayList<PasswordMap>> rainbow;
public HashMap() {
password = "";
hash = -1L;
key = -1;
initializeHashMap();
}
public HashMap(String str) {
password = str;
hash = hashCode(str);
key = (int)(hash % 29);
initializeHashMap();
}
private void initializeHashMap() {
//Initialize an ArrayList of 29 elements - when dividing by 29 only remainders 0 - 28 are possible
rainbow = new ArrayList<>();
for(int i = 0; i < 29; i++) {
rainbow.add(new ArrayList<PasswordMap>());
}
compute();
}
public Long hashCode(String str) throws InvalidPasswordException{
this.hash = 0L;
//TODO: Calculate hashCode using hashing function based on powers of 29
return 0L; // temp - delete once hashCode method is implemented.
}
public void compute() {
//TODO: Add code to compute all possible 4-letter passwords - store in rainbow
// Begin your possible passwords with aaaa and end with zzzz
// Use hashCode(pwd) % 29 to determine the key (index) of where this element should be added to rainbow's ArrayList of ArrayLists
// You will need to cast as int, such as key = (int) hashCode(pwd)%29 - key is the index of where to add this element in the rainbow ArrayList of ArrayLists
if(password.length() != passwordLength){
throw new InvalidPasswordException();
}
while(password.startsWith("aaaa") && password.endsWith("zzzz")){
key = (int) (hashCode(password)%29);
rainbow.add(key, password);
}
}
public Long hash(String pwd) {
//TODO: Return the hashcode for a given password
// First, hash the password: int key = (int)(hashCode(pwd) % 29);
// Use this key to determine which element in the rainbow table you should be traversing to find the hash code
// Recall rainbow is an ArrayList of ArrayLists!!
key = (int)(hashCode(pwd)%29);
return 0L; // temp - delete once hash method is implemented.
}
public String hack(Long pwdHash) {
String pwd="";
//TODO: Given a hashed password, pwdHash, determine the password
// When identifying a correct hashed password, you will need to look at a difference RATHER THAN ==
// That is,
//if (Math.abs(pwdHash - rainbow.get(key).get(i).getHash())<.001) - you've found your password!!
// Note: key is the location of the rainbow list you should be traversing: key = (int)((pwdHash) % 29);
return pwd;
}
@Override
public String toString() {
return password + ": " + hash;
}
}
最佳答案
这里的问题是您的while
循环。while(f())
表示“只要f()
返回true,请继续这样做”。
您已经说过“只要password
以“ aaaa”开头并且password
以“ zzzz”结尾,就继续这样做。
我们看不到您初始化password
,但是如果它是如上所述的四个字符的字符串,则不可能以“ aaaa”开头和以“ zzzz”结尾,因此while循环的块将永远不会执行。
如果password
是"aaaazzzz"
,那么条件成立,那么,由于您从不修改password
的值,因此while循环将永远重复。
您可能想要类似:
for(int i=0;; i++) {
String password = createPassword(i);
rainbow.add(password, hash(password));
}
...并编写方法
createPassword()
,使createPassword(0)
返回“ aaaa”,createPassword(1)
返回“ aaab”,createPassword(26)
返回“ aaba”,依此类推。