我试图在一行代码中获得多个输入。
例如在c ++中,我们可以像这样-

int a,b,c;
cin>>a>>b>>c;


Java中也有可能吗?

最佳答案

您可以为此使用数组,例如:

public static void main(String[] args) {
        int[] values = new int[3];
        Scanner in = new Scanner(System.in);
        for(int i = 0; i < values.length; i++) {
            values[i] = in.nextInt();
        }
        System.out.println(Arrays.toString(values));
    }


更新2

在Java 8中,上述解决方案可以使用较短的版本:

Scanner in = new Scanner(System.in);
Integer[] inputs = Stream.generate(in::nextInt).limit(3).toArray(Integer[]::new);


更新1

还有另一种方法,它更接近cin

public class ChainScanner {
        private Scanner scanner;

        public ChainScanner(Scanner scanner) {
            this.scanner = scanner;
        }

        public ChainScanner readIntTo(Consumer<Integer> consumer) {
            consumer.accept(scanner.nextInt());
            return this;
        }

        public ChainScanner readStringTo(Consumer<String> consumer) {
            consumer.accept(scanner.next());
            return this;
        }
    }

    public class Wrapper {
        private int a;
        private int b;
        private String c;

        public void setA(int a) {
            this.a = a;
        } /* ... */
    }

    public static void main(String[] args) {
        ChainScanner cs = new ChainScanner(new Scanner(System.in));
        Wrapper wrapper = new Wrapper();

        cs.readIntTo(wrapper::setA).readIntTo(wrapper::setB).readStringTo(wrapper::setC);

        System.out.println(wrapper);
    }

10-05 22:07