php - 尝试在函数中使用私有(private)变量时出现错误代码

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8年前关闭。




我收到一个错误提示



在尝试运行我的脚本时。我是 PHP 类的新手，想知道是否有人可以指出我的错误。这是该部分的代码。

<?php
class ac
  {
  public function authentication()
    {
    private $plain_username = $_POST['username'];
    private $md5_password = md5($_POST['password']);

    $ac = new ac();

最佳答案

您不在函数/方法中定义类属性(公共(public)/私有(private)/等)。你在类(class)的主体中做这件事。

class ac
{
    private $plain_username;
    private $md5_password;

    public function authentication()
    {
        $this->plain_username = $_POST['username'];
        $this->md5_password = md5($_POST['password']);
    }
}

//declare a class outside the class
$ac = new ac();

如果要在函数/方法中定义变量，只需在不使用public/private/protected的情况下声明它们

$plain_username = $_POST['username'];

关于php - 尝试在函数中使用私有(private)变量时出现错误代码，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/2496053/