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Relative Strength Index in python pandas
(11 个回答)
12 个月前关闭。
我从外汇市场获得了一个具有值(value)的 df,我正在尝试将 df 中每一行的 RSI、相对强度指数 (10) 放入数据框中。
(11 个回答)
12 个月前关闭。
我从外汇市场获得了一个具有值(value)的 df,我正在尝试将 df 中每一行的 RSI、相对强度指数 (10) 放入数据框中。
df.head()
Out[3]:
Date Time Open High Low Close Volume OpenInt
0 2016-09-16 00:05:00 0.75183 0.75186 0.75160 0.75161 0 0
1 2016-09-16 00:10:00 0.75156 0.75156 0.75145 0.75149 0 0
2 2016-09-16 00:15:00 0.75156 0.75166 0.75152 0.75165 0 0
3 2016-09-16 00:20:00 0.75164 0.75165 0.75150 0.75156 0 0
4 2016-09-16 00:25:00 0.75156 0.75174 0.75153 0.75156 0 0
RSI 是一个指标,告诉您产品何时超卖或超买; RSI = 100 - 100/(1 + RS) 其中 RS 是给定时间范围内上行周期的平均增益/给定时间范围内下行周期的平均损失。就我而言,时间范围是 10。df.change = df.Open - df.Close # find out if there is a gain or a loss
df.gain = df.change [df.change > 0] #column of gain
df.loss = df.change [df.change < 0]# column of loss
df.again = df.gain.rolling(center=False,window=10) #find the average gain in the last 10 periods
df.aloss = df.loss.rolling(center=False,window=10) #find the average loss in the last 10 periods
现在是麻烦开始的地方;我需要得到 RS:df.rs = df.again/df.aloss
TypeErrorTraceback (most recent call last)
<ipython-input-13-2886bcd78f42> in <module>()
----> 1 df.rs = df.again/df.aloss
TypeError: unsupported operand type(s) for /: 'Rolling' and 'Rolling'
编辑df.gain.head(6)
Out[31]:
0 0.00022
1 0.00007
3 0.00008
5 0.00002
7 0.00003
8 0.00002
df.loss.head(6)
Out[32]:
2 -0.00009
6 -0.00019
9 -0.00013
14 -0.00002
15 -0.00011
20 -0.00008
dtype: float64
最佳答案
delta = df.Close.diff()
window = 15
up_days = delta.copy()
up_days[delta<=0]=0.0
down_days = abs(delta.copy())
down_days[delta>0]=0.0
RS_up = up_days.rolling(window).mean()
RS_down = down_days.rolling(window).mean()
rsi= 100-100/(1+RS_up/RS_down)
关于python - 从 Pandas 数据帧计算 RSI,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/39702156/
10-11 02:17