我似乎无法使markerLabel访问locations数组中的位置i,1。我已经移动了它,无论我放置在什么地方,它都会对所有6个markerLabel(位置[5] [1])返回45。我应该在循环中运行一个markerLabel 31,markerLabel 33,markerLabel 34等。位置[i] [0]中找到的地址全部正确显示。我已经评论了我认为应该去的次要地方,并把它留在了我认为应该的地方。我所缺少的任何见解将不胜感激。

    <!DOCTYPE html>
<html>
<head>
  <meta http-equiv="content-type" content="text/html; charset=UTF-8" />
  <title>Google Maps Multiple Markers</title>
  <script src="http://maps.google.com/maps/api/js?sensor=false"
          type="text/javascript"></script>
  <script src="http://ajax.googleapis.com/ajax/libs/jquery/1.8.0/jquery.min.js"></script>

</head>
<body>
    <div id="map" style="width: 500px; height: 400px;"></div>



<script type="text/javascript">
    $(document).ready(function () {
    var locations = [
        ['3026 East College Ave, Ruskin, Fl, USA','31'],
        ['517 19th Street Northwest, Ruskin, Fl, USA','33'],
        ['101 College Avenue East, Ruskin, Fl, USA','34'],
        ['3350 Laurel Ridge Ave, Ruskin, Fl, USA','37'],
        ['409 Laguna Mill Dr, Ruskin, Fl, USA','40'],
        ['2302 Lloyd Dr, Ruskin, Fl, USA','45']
        ];

    var map = new google.maps.Map(document.getElementById('map'), {
      zoom: 12,
      center: new google.maps.LatLng(27.714616,-82.393298),
      mapTypeId: google.maps.MapTypeId.HYBRID
    });


    var marker, i, markerLabel;

    for (i = 0; i < locations.length; i++) {
     var markerLabel = locations[i][1];
        $.getJSON('http://maps.googleapis.com/maps/api/geocode/json?address='+locations[i][0]+'&sensor=false', null, function (data) {
            var p = data.results[0].geometry.location
          //var markerLabel = locations[i][1];
           marker = new google.maps.Marker({
                position: new google.maps.LatLng(p.lat, p.lng),
                map: map,
                label: {
                    //text: locations[i][1];
                    text: markerLabel,
                    color: "#fff",
                    fontSize: "16px",
                    fontWeight: "bold"
                } //label
            }); // Marker

        }); //$.getJSON
    } //for (i = 0; i < locations.length; i++)

}); //$(document).ready(function ()

</script>

最佳答案

$.getJSON的调用是异步的。这意味着,循环将立即运行其所有迭代,并触发这些异步调用。在任何ajax调用完成之前,它将快速连续地更改imarkerValue的值6次,然后当这些函数最终完成并触发其回调时,它们最终将访问其值中已更改的值。范围,最终得到相同的结果。

您需要隔离单个ajax请求的范围,以使它们不都引用相同的变量。这应该足以做到这一点:

function make_request(i) {
    $.getJSON('http://maps.googleapis.com/maps/api/geocode/json?address='+locations[i][0]+'&sensor=false', null, function (data) {
       var p = data.results[0].geometry.location
       marker = new google.maps.Marker({
            position: new google.maps.LatLng(p.lat, p.lng),
            map: map,
            label: {
                text: locations[i][1],
                color: "#fff",
                fontSize: "16px",
                fontWeight: "bold"
            } //label
        }); // Marker

    }); //$.getJSON
}

for (i = 0; i < locations.length; i++) {
    make_request(i);
} //for (i = 0; i < locations.length; i++)

08-08 03:47