我正在接收错误[语法错误]行0,列257:错误:应为=,,>,>=!=,执行此条令查询生成器查询时得到“18”。数据库是pgSQL。
$query = $this->entityManager
->createQueryBuilder()
->select('s.subscriptionReference')
->from(
'OTDatabase\Entity\Membership\Member',
'm'
)
->innerJoin(
'OTDatabase\Entity\Membership\MemberSubscriptions',
's',
'WITH',
'm.record = s.memberReference'
);
$query
->andWhere('s.list = 1');
$query
->andWhere('m.validated IN (:validated)')
->setParameter('validated', array('1', '3'));
$query
->andWhere($query->expr()->lt(gmdate('Y-m-d H:i:s') , 's.subscription_begins'));
$query
->andWhere('
(
( now() <= s.subscriptionExpires )
OR
( s.subscriptionBegins <= now() AND s.subscriptionExpires IS NULL )
)');
$result = $query->getQuery()
->getArrayResult();
为了将来参考,正确的查询(借助@Logan Bailey)是:
$query = $this->entityManager
->createQueryBuilder()
->select('s.subscriptionReference')
->from(
'OTDatabase\Entity\Membership\Member',
'm'
)
->innerJoin(
'OTDatabase\Entity\Membership\MemberSubscriptions',
's',
'WITH',
'm.record = s.memberReference'
);
$query
->andWhere('s.list = 1');
$query
->andWhere('m.validated IN (:validated)')
->setParameter('validated', array('1', '3'));
$query
->andWhere($query->expr()->lt('s.subscriptionBegins' , ':subscriptionDate'))
->setParameter('subscriptionDate', gmdate('Y-m-d H:i:s'));
$query
->andWhere($query->expr()->orX(
$query->expr()->lt(':subscriptionDate' , 's.subscriptionExpires'),
$query->expr()->isNull('s.subscriptionExpires')
));
最佳答案
你得用引号把日期括起来。您可能应该将其用作绑定参数。
$query
->andWhere($query->expr()->lt(':subscriptionDate' , 's.subscription_begins'))
->setParameter('subscriptionDate', gmdate('Y-m-d H:i:s'));
关于postgresql - 将pgSQL转换为学说,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/32317598/