要输出该程序,它告诉两个单词是否是字谜。我想知道如何将所有System.out.print命令更改为JOption Pane命令!我很乐意提供帮助,因为我是一名1年级程序员,并且有此任务。
import java.util.Arrays;
public class NewAnagram
{
public static void main(String[] args)
{
if (args.length != 2)
{
System.out.println("2 words have not been entered!");
}
else
{
printPhrases(args[0], args[1]);
}
}
public static boolean anagramSearch(String phrase1, String phrase2)
{
String ltrsOnlyOne = lettersOnly(phrase1);
String ltrsOnlyTwo = lettersOnly(phrase2);
char[] first = ltrsOnlyOne.toLowerCase().toCharArray();
char[] second = ltrsOnlyTwo.toLowerCase().toCharArray();
Arrays.sort(first);
Arrays.sort(second);
if (Arrays.equals(first, second))
{
return true;
}
else
{
return false;
}
}
public static String lettersOnly(String word)
{
int length = word.length();
StringBuilder end = new StringBuilder(length);
char j;
for (int i = (length - 1); i >= 0; i--)
{
j = word.charAt(i);
if (Character.isLetter(j))
{
end.append(j);
}
}
return end.toString();
}
public static void printPhrases(String phrase1, String phrase2)
{
boolean isFound = anagramSearch(phrase1, phrase2);
if (isFound == true)
{
System.out.println(phrase1 + " is an anagram of "+ phrase2);
}
if (isFound == false)
{
System.out.println(phrase1 + " is not an anagram of "+ phrase2);
}
}
}
最佳答案
像这样的线
System.out.println(phrase1 + " is not an anagram of "+ phrase2);
将在JOptionPane版本中,如下所示:
JOptionPane.showMessageDialog(null, phrase1 + " is not an anagram of " + phrase2);
其中第一个参数是对话框的父级。由于您的应用程序中没有其他窗口,因此只需传递
null
。