java - hibernate :java.sql.SQLIntegrityConstraintViolationException:无法添加或更新子行:外键约束失败

我正在尝试在Jpa中建立一对一的关系。当我运行该程序时，抛出异常

ERROR: Cannot add or update a child row: a foreign key constraint fails (`ngsharma`.`student`, CONSTRAINT `FK8nqh8nm4hrwx9hlqwhxf6kfen` FOREIGN KEY (`laptop_lid`) REFERENCES `laptop` (`lid`))

学生

@Entity(name = "student")
public class Student {

    @Id
    private  int rollno;
    private String name;
    @OneToOne
    private Laptop laptop;

    /*Setter & Getter*/
}

笔记本电脑

@Entity(name = "laptop")
public class Laptop {

    @Id
    private int lid;
    private String laptopName;

    /*Setter & Getter*/
}

Hibernate.cfg.xml

<hibernate-configuration>
    <session-factory>
        <property name="hibernate.connection.driver_class">com.mysql.cj.jdbc.Driver</property>
        <property name="hibernate.connection.password">root</property>
        <property name="hibernate.connection.url">jdbc:mysql://localhost:3306/ngsharma</property>
        <property name="hibernate.connection.username">root</property>
        <property name="hibernate.dialect">org.hibernate.dialect.MariaDBDialect</property>
        <property name="hbm2ddl.auto">create</property>
        <property name="show_sql">true</property>
    </session-factory>
</hibernate-configuration>

运行CLass

    Configuration configuration =
            new Configuration().configure()
                                                    .addAnnotatedClass(Student.class).addAnnotatedClass(Laptop.class);

    SessionFactory sessionFactory = configuration.buildSessionFactory();

    Session session = sessionFactory.openSession();

    Laptop laptop = new Laptop();
    laptop.setLid(101);
    laptop.setLaptopName("Mac Nootbook");

    Student student = new Student();
    student.setRollno(1);
    student.setName("Shri Krishan");
    student.setLaptop(laptop);

     Serializable serializable = session.save(student);
     System.out.println("Test Code : "  + serializable);

     session.beginTransaction().commit();

最佳答案

在您的示例中，您尝试保存一个student实体，对于该实体，数据库中不存在laptop关联。根据您提供的代码片段，这两个实例都是新创建的。因此，根据数据库级别的外部约束，您尝试从laptop表中引用student表；其中带有引用的laptop的相应id行不存在。

如果在持久化laptop实体的同时还持久化关联的student实体，则将解决问题。您需要做的唯一修改就是将@OneToOne关系更新为：

    @OneToOne(cascade=CascadeType.PERSIST)
    private Laptop laptop;

这将起作用；因为它还会将laptop实体以及student实体本身插入数据库中。