一个非常简单的计算行进距离的程序(一周前才开始),我使这个循环适用于是非题,但我希望它适用于简单的“是”或“否”。我为此分配的字符串是答案。

public class Main {

public static void main(String[] args) {

    Scanner input = new Scanner(System.in);

    double distance;
    double speed;
    boolean again = true;
    String answer;

    do{
        System.out.print("Tell me your distance in miles: ");
        distance = input.nextDouble();
        System.out.print("Tell me your speed in which you will travel: ");
        speed = input.nextDouble();

        double average = distance / speed;

        System.out.print("Your estimated time to your destination will be: " + average + " hours\n\n");

        if(average < 1){
            average = average * 10;
            System.out.println(" or " + average + " hours\n\n");
        }

        System.out.println("Another? ");
        again = input.nextBoolean();

    }while(again);

}

}

最佳答案

您需要使用input.next()而不是input.nextBoolean(),并将结果与​​字符串文字"yes"(大概是不区分大小写的方式)进行比较。请注意,again的声明需要从boolean更改为String

String again = null;
do {
    ... // Your loop
    again = input.nextLine(); // This consumes the \n at the end
} while ("yes".equalsIgnoreCase(again));

10-04 23:36