java - 为什么此代码在Vista中而不在7中有效？

出于某种原因，每次有人让我在Vista中运行该程序时，它都可以正常运行，但是一旦将其移到Windows 7 PC上，它就会停在ActionListener的Action Performed方法的中间，这意味着我可以单击选择，但永远不会说选择尺寸。
有没有什么办法解决这一问题？

import java.io.*;
import java.util.*;
import java.awt.*;
import javax.swing.*;
import java.awt.event.*;
public class SizerFrame extends JFrame {
    ButtonGroup buttons = new ButtonGroup();
    JTextField width = new JTextField(2);
    JTextField height = new JTextField(2);
    double inchesPerTimeline = 2.1;
    public SizerFrame()
    {
        super("Timeline Application");
        Dimension screen = Toolkit.getDefaultToolkit().getScreenSize();
        setBounds(screen.width/2-125,screen.height/2-90,250,180);
        getContentPane().setLayout(new GridBagLayout());
        GridBagConstraints c = new GridBagConstraints();
        int[] gridX = new int[]{0,0,0,0};
        int[] gridY = new int[]{0,1,2,3};
        int[] gridW = new int[]{1,1,2,5};
        String[] titles = new String[]{"6\"","9\"","10\"","Custom"};
        String[] actions = new String[]{"6","9","10","C"};
        for (int a = 0; a < 4; a++)
        {
            JRadioButton current = new JRadioButton(titles[a]);
            current.setActionCommand(actions[a]);
            c.gridx = gridX[a];
            c.gridy = gridY[a];
            c.gridwidth = gridW[a];
            buttons.add(current);
            getContentPane().add(current,c);
        }
        c.gridwidth = 1;
        String[] title = new String[]{"      ","Width","Height"};
        gridX = new int[]{9,10,12};
        for (int a = 0; a< 3; a++)
        {
            c.gridx = gridX[a];
            getContentPane().add(new JLabel(title[a]),c);
        }
        c.gridx = 11;
        getContentPane().add(width,c);
        c.gridx = 13;
        getContentPane().add(height,c);
        c.gridx = 11;
        c.gridy = 0;
        c.gridwidth = 2;
        JButton button = new JButton("Done");
        button.addActionListener(new ActionListener() {
            public void actionPerformed(ActionEvent e) {
                ButtonModel x = buttons.getSelection();
                String size = "XXX";
                System.out.println("Getting screen resolution");
                int screenRes = Toolkit.getDefaultToolkit().getScreenResolution();
                System.out.println("Successfully got screen resolution");
                if (x!=null)
                    size = x.getActionCommand();
                try{
                    TimeTable.width = new Integer(size)*screenRes;
                    TimeTable.height = (int)((TimeTable.titleCount+1)*inchesPerTimeline*screenRes);
                }
                catch(NumberFormatException ex)
                {
                    try{
                        TimeTable.width = (int)(new Double(width.getText().trim())*screenRes);
                        TimeTable.height = (int)(new Double(height.getText().trim())*screenRes);
                    }
                    catch (NumberFormatException except)
                    {
                        return;
                    }
                }
                TimeTable.ready = true;
                System.out.println("Size selected");
                dispose();
            }
        });
        getContentPane().add(button,c);
        addWindowListener(new WindowAdapter() {
            public void windowClosing(WindowEvent winEvt){
                System.exit(0);
            }
        });
        setVisible(true);
    }
}

简要说明：
我有一个在Windows Vista中用完Excel的宏，我试图将其分发给运行Windows 7的计算机。执行后，此刻代码无法继续执行，即，它从未打印出“选择大小”字样。该程序的其余部分从C：\ Users \？\ AppData \ TimeLineMacroProgram文件夹中导入一个csv文件，然后在同一目录中创建一个映像。但这是当前已损坏的代码部分。每当GUI弹出时，我都选择9的选项，然后单击完成，它应该将9作为参数传递，然后打印出“选择的大小”，但它不是唯一地放置窗口。请帮忙。

最佳答案

长镜头猜测：

如果width和height文本字段不包含内容，则动作侦听器将退出：您将在两个NumberFormatExceptions之后返回。这将阻止显示“选择的尺寸”，并且不放置框架。如果获得“成功获得屏幕分辨率”输出，然后似乎停止工作，则可能是原因。但是，如果您遇到这种情况，然后单击其他内容然后单击“完成”，它将打印选定的尺寸。