php - AES加密不同于节点和PHP

我有两个脚本，都使用相同的算法用相同的密钥和IV加密字符串。但是结果是不同的。 openssl_encrypt是否仍使用与节点不同的填充方案，还是我缺少其他东西？

节点

const crypto = require('crypto');

var passphrase = '29486a7a37664140';
var iv = '76e69938cdf5bb64';
var text = '1234567890123456';

var cipher = crypto.createCipheriv('aes-128-ctr', passphrase, iv)
var crypted = cipher.update(text,'utf8','hex')
crypted += cipher.final('hex');

var result = crypted + ':' + iv;

console.log('crypted: (' + crypted.length + ' chars)', crypted);
// crypted: (32 chars) b94107e56900ec8270a847bbf457eaa6

的PHP

<?php

$encrypt_method = "AES-128-CTR";
$passphrase = '29486a7a37664140';
$iv = '76e69938cdf5bb64';
$text = '1234567890123456';

$encrypted = openssl_encrypt( $text, $encrypt_method, $passphrase, 0, $iv );

echo 'crypted (' . strlen($encrypted) . ' chars): ' . $encrypted;
// crypted (24 chars): uUEH5WkA7IJwqEe79Ffqpg==
?>

最佳答案

好吧，嗯……愚蠢。编码问题：

更改我的节点部分以使用bas64

var cipher = crypto.createCipheriv('aes-128-ctr', passphrase, iv)
var crypted = cipher.update(text,'utf8','base64')
crypted += cipher.final('base64');