这样做会被认为是好的做法吗…
我有以下定义的A级:

 class A{
      private $_varOne;
      private $_varTwo;
      private $_varThree;
      public $varOne;


      public function __get($name){

   $fn_name = 'get' . $name;

         if (method_exists($this, $fn_name)){
             return $this->$fn_name();
   }else if(property_exists('DB', $name)){
             return $this->$name;
   }else{
    return null;
   }
      }

  public function __set($name, $value){

   $fn_name = 'set' . $name;

   if(method_exists($this, $fn_name)){
    $this->$fn_name($value);
   }else if(property_exists($this->__get("Classname"), $name)){
    $this->$name = $value;
   }else{
    return null;
   }

  }

      public function get_varOne(){
           return $this->_varOne . "+";
      }


 }

 $A = new A();
 $A->_varOne;     //For some reason I need _varOne to be returned appended with a +

 $A->_varTwo;     //I just need the value of _varTwo

为了不创建4个set和4个get方法,我使用了magic方法来为我需要的属性调用受人尊敬的getter,或者只返回属性的值而不做任何更改。这可以看作是一种好的做法吗?

最佳答案

不知道最佳实践,但当需要延迟加载属性时(例如,当获取涉及复杂钙化或数据库查询时),g e t会非常有用。此外,php通过简单地创建同名的对象字段来提供缓存响应的优雅方法,从而防止再次调用getter。

class LazyLoader
{
    public $pub = 123;

    function __get($p) {
        $fn = "get_$p";
        return method_exists($this, $fn) ?
            $this->$fn() :
            $this->$p; // simulate an error
    }

    // this will be called every time
    function get_rand() {
        return rand();
    }

    // this will be called once
    function get_cached() {
        return $this->cached = rand();
    }
}

$a = new LazyLoader;
var_dump($a->pub);       // getter not called
var_dump($a->rand);      // getter called
var_dump($a->rand);      // once again
var_dump($a->cached);    // getter called
var_dump($a->cached);    // getter NOT called, response cached
var_dump($a->notreally); // error!

08-07 07:55