当我尝试使用以下代码从Oracle数据库读取数据时,出现异常

ResultSet res=stmt.executeQuery("select * from food");

但是,当我直接在命令提示符下使用此命令时,此表实际上存在于我的数据库中。并且对于数据库中表中的一个表,此代码也可以正常工作,但对于其他表名,其代码无法正常工作。有人请解释为什么会这样。
java.sql.SQLSyntaxErrorException: ORA-00942: table or view does not exist

    at oracle.jdbc.driver.T4CTTIoer.processError(T4CTTIoer.java:440)
    at oracle.jdbc.driver.T4CTTIoer.processError(T4CTTIoer.java:396)
    at oracle.jdbc.driver.T4C8Oall.processError(T4C8Oall.java:837)
    at oracle.jdbc.driver.T4CTTIfun.receive(T4CTTIfun.java:445)
    at oracle.jdbc.driver.T4CTTIfun.doRPC(T4CTTIfun.java:191)
    at oracle.jdbc.driver.T4C8Oall.doOALL(T4C8Oall.java:523)
    at oracle.jdbc.driver.T4CStatement.doOall8(T4CStatement.java:193)
    at oracle.jdbc.driver.T4CStatement.executeForDescribe(T4CStatement.java:852)
    at oracle.jdbc.driver.OracleStatement.executeMaybeDescribe(OracleStatement.java:1153)
    at oracle.jdbc.driver.OracleStatement.doExecuteWithTimeout(OracleStatement.java:1275)
    at oracle.jdbc.driver.OracleStatement.executeQuery(OracleStatement.java:1477)
    at oracle.jdbc.driver.OracleStatementWrapper.executeQuery(OracleStatementWrapper.java:392)
    at connecttooracle.ConnectOracle.main(ConnectOracle.java:67)

我正在从Toad访问食物表中的数据。为什么我在Java中遇到此错误?

我的完整代码是:
public class ConnectOracle {

 public static void main(String[] args) {

  String driver = "oracle.jdbc.driver.OracleDriver"; //

  String serverName = "10.11.201.84";
  String portNumber = "1521";
  String db = "XE";
  String url = "jdbc:oracle:thin:@" + serverName + ":" + portNumber + ":"
    + db; // connectOracle is the data
  // source name
  String user = "ORAP"; // username of oracle database
  String pwd = "ORAP"; // password of oracle database
  Connection con = null;
  ServerSocket serverSocket = null;
  Socket socket = null;
  DataInputStream dataInputStream = null;
  DataOutputStream dataOutputStream = null;

  try {
   Class.forName(driver);// for loading the jdbc driver

   System.out.println("JDBC Driver loaded");

   con = DriverManager.getConnection(url, user, pwd);// for
                // establishing
   // connection
   // with database
   Statement stmt = (Statement) con.createStatement();

   serverSocket = new ServerSocket(8888);
   System.out.println("Listening :8888");

   while (true) {
    try {

     socket = serverSocket.accept();
     System.out.println("Connection Created");
     dataInputStream = new DataInputStream(
       socket.getInputStream());
     dataOutputStream = new DataOutputStream(
       socket.getOutputStream());
     System.out.println("ip: " + socket.getInetAddress());
     // System.out.println("message: " +
     // dataInputStream.readUTF());

     ResultSet res=stmt.executeQuery("select * from food");
     while(res.next()){
      System.out.println(res.getString(1));
     }

    } catch (IOException e) {
     // TODO Auto-generated catch block
     e.printStackTrace();
    }

    if (dataInputStream != null) {
     try {
      dataInputStream.close();
     } catch (IOException e) {
      // TODO Auto-generated catch block
      e.printStackTrace();
     }
    }

    if (dataOutputStream != null) {
     try {
      dataOutputStream.close();
     } catch (IOException e) {
      // TODO Auto-generated catch block
      e.printStackTrace();
     }
    }
   }
  } catch (Exception e) {
   // TODO Auto-generated catch block
   e.printStackTrace();
  }
 }
}

最佳答案

如果您的表位于模式A下:

select * from A.food

编辑

如果您可以使用用户ORAP通过TOAD登录并执行相同的查询(从food中选择*),那么您肯定会将表包含在ORAP模式中。我没有理由“从ORAP.food中选择*”失败。

08-07 05:05