我正在使用SQL 2008,只是无法使该查询正常工作。我有一张桌子,上面有航班价格的详细信息。每条路线每天都有很多行,我想返回该路线每天的最低价格以及DateAdded(添加行的日期时间)。我快要到达了,因为我似乎已经设法获得了每天最低的价格,但是我似乎无法获得正确的日期补交。下面的代码似乎可以返回每天的最低价格,但是我想我需要某种联接才能返回DateAdded?

ALTER PROCEDURE [dbo].[FlightInfoLowestPricePerDay]
(
@AirportFrom    varchar(5),
@AirportTo      varchar(5)
)

AS
select  DATEADD(dd, 0, DATEDIFF(dd, 0, TimeDeparture)) as FlightDate, MIN(Price) as MinPrice


from FlightInfo
where AirportFrom = @AirportFrom and AirportTo = @AirportTo
AND TimeDeparture > DATEADD(dd, 0, DATEDIFF(dd, 0, GETDATE()))

Group By DATEADD(dd, 0, DATEDIFF(dd, 0, TimeDeparture))
Order by FlightDate ASC


我已经尝试了下面的代码之类的东西,但是我还不完全了解联接,因此尽管已经确定我很想念一些简单的东西,但已经挣扎了一段时间。

ALTER PROCEDURE [dbo].[FlightInfoLowestPricePerDay]
(
@AirportFrom    varchar(5),
@AirportTo      varchar(5)
)

AS
select  DATEADD(dd, 0, DATEDIFF(dd, 0, fi1.TimeDeparture)) as FlightDate, MIN(fi1.Price)     as       MinPrice, fi2.DateAdded


from FlightInfo
fi1 join FlightInfo fi2 on fi1.Price = fi2.Price
where fi1.AirportFrom = @AirportFrom and fi1.AirportTo = @AirportTo
AND fi1.TimeDeparture > DATEADD(dd, 0, DATEDIFF(dd, 0, GETDATE()))

Group By DATEADD(dd, 0, DATEDIFF(dd, 0, fi1.TimeDeparture))
Order by FlightDate ASC

最佳答案

添加fi2.Date已添加到分组依据

ALTER PROCEDURE [dbo].[FlightInfoLowestPricePerDay]
(
@AirportFrom    varchar(5),
@AirportTo      varchar(5)
)

AS
select  DATEADD(dd, 0, DATEDIFF(dd, 0, fi1.TimeDeparture)) as FlightDate, MIN(fi1.Price)     as       MinPrice, Cast(Convert(varchar(20),fi2.DateAdded,101) as datetime) DateAdded


from FlightInfo
fi1 join FlightInfo fi2 on fi1.Price = fi2.Price
where fi1.AirportFrom = @AirportFrom and fi1.AirportTo = @AirportTo
AND fi1.TimeDeparture > DATEADD(dd, 0, DATEDIFF(dd, 0, GETDATE()))

Group By DATEADD(dd, 0, DATEDIFF(dd, 0, fi1.TimeDeparture)),Cast(Convert(varchar(20),fi2.DateAdded,101) as datetime)
Order by FlightDate ASC

10-07 15:53