我想在Kotlin中转换此方法,但我不知道要正确执行操作并具有正确的操作记忆的变量是什么:
public static UUID bytestoUUID(byte[] buf, int offset) {
long lsb = 0;
for (int i = 15; i >= 8; i--) {
lsb = (lsb << 8) | (buf[i + offset] & 0xff);
}
long msb = 0;
for (int i = 7; i >= 0; i--) {
msb = (msb << 8) | (buf[i + offset] & 0xff);
}
return new UUID(msb, lsb);
}
你有正确的方法吗?谢谢
最佳答案
它应该是
import java.util.*
import kotlin.experimental.and
fun bytestoUUID(buf: ByteArray, offset: Int): UUID {
var lsb: Long = 0
for (i in 15 downTo 8) {
lsb = lsb shl 8 or ((buf[i + offset] and 0xff.toByte()).toLong())
}
var msb: Long = 0
for (i in 7 downTo 0) {
msb = msb shl 8 or ((buf[i + offset] and 0xff.toByte()).toLong())
}
return UUID(msb, lsb)
}