对于我的项目,我必须使用jsgrid(http://js-grid.com)。

为了测试是否使用jsgrid,我想做一个“入门”示例(http://js-grid.com/getting-started
我的问题是,按照我的观点,我做了所有的事,但最终还是没有用。

我想念什么?

这是我的代码:



<!DOCTYPE html>
<html>
<head>
    <link type="text/css" rel="stylesheet" href="https://cdnjs.cloudflare.com/ajax/libs/jsgrid/1.5.3/jsgrid.min.css" />
    <link type="text/css" rel="stylesheet" href="https://cdnjs.cloudflare.com/ajax/libs/jsgrid/1.5.3/jsgrid-theme.min.css" />

    <script src="https://ajax.googleapis.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
    <script type="text/javascript" src="https://cdnjs.cloudflare.com/ajax/libs/jsgrid/1.5.3/jsgrid.min.js"></script>
    <script>
        var clients = [
            { "Name": "Otto Clay", "Age": 25, "Country": 1, "Address": "Ap #897-1459 Quam Avenue", "Married": false },
            { "Name": "Connor Johnston", "Age": 45, "Country": 2, "Address": "Ap #370-4647 Dis Av.", "Married": true },
            { "Name": "Lacey Hess", "Age": 29, "Country": 3, "Address": "Ap #365-8835 Integer St.", "Married": false },
            { "Name": "Timothy Henson", "Age": 56, "Country": 1, "Address": "911-5143 Luctus Ave", "Married": true },
            { "Name": "Ramona Benton", "Age": 32, "Country": 3, "Address": "Ap #614-689 Vehicula Street", "Married": false }
        ];

        var countries = [
            { Name: "", Id: 0 },
            { Name: "United States", Id: 1 },
            { Name: "Canada", Id: 2 },
            { Name: "United Kingdom", Id: 3 }
        ];

        $("#jsGrid").jsGrid({
            width: "100%",
            height: "400px",

            inserting: true,
            editing: true,
            sorting: true,
            paging: true,

            data: clients,

            fields: [
                { name: "Name", type: "text", width: 150, validate: "required" },
                { name: "Age", type: "number", width: 50 },
                { name: "Address", type: "text", width: 200 },
                { name: "Country", type: "select", items: countries, valueField: "Id", textField: "Name" },
                { name: "Married", type: "checkbox", title: "Is Married", sorting: false },
                { type: "control" }
            ]
        });
    </script>
</head>
<body>
    <div id="jsGrid"></div>
</body>
</html>

最佳答案

您的脚本代码将在DOM准备就绪之前运行。我将您的脚本包裹在两个脚本之间:

$(document).ready(function() {


和:

});


并与显示的表格运行良好。有关某些说明,请参见here

jsGrid是一个很棒的工具。不幸的是,它的诊断几乎为零。可能是错误的,例如简单的错字,但根本没有任何错误的迹象。

关于javascript - jsgrid入门示例不起作用,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/51730839/

10-12 18:39