我正在编写的代码有两个类:writeInts和readInts。我编写了writeInts以随机生成0到1000之间的100个数字,并将它们输出到data.dat文件。

readInts应该打开一个DataInputStream对象,并从data.dat文件中读取“原始”数据,并将100个整数存储在数组中。我的问题是我似乎无法正确读取数据。任何帮助,将不胜感激。谢谢!

writeInts:

import java.io.*;


public class WriteInts {
    public static void main(String[] args) throws IOException {
        DataOutputStream output = new DataOutputStream(new FileOutputStream("data.dat"));
        int num = 0 + (int)(Math.random());
        int[] counts = new int[100];
        for(int i=0; i<100; i++) {
            output.writeInt(num);
            counts[i] += num;

            System.out.println(num);
        }
        output.close();
    }

}


readInts:

import java.io.*;
import java.util.*;

public class ReadInts {
    public static void main(String[] args) throws IOException {

        // call the file to read
        Scanner scanner = new Scanner(new File("data.dat"));
        int[] data = new int[100];
        int i = 0;
        while (scanner.hasNextInt()) {
            data[i++] = scanner.nextInt();

            System.out.println(data[i]);

            scanner.close();
        }

    }

}

最佳答案

如果要写入二进制数据,请使用DataInputStream / DataOutputStream。扫描仪用于文本数据,您不能混合使用。

WriteInts:

import java.io.*;

public class WriteInts {
    public static void main(String[] args) throws IOException {
        DataOutputStream output = new DataOutputStream(new FileOutputStream(
                "data.dat"));

        for (int i = 0; i < 100; i++) {
            output.writeInt(i);
            System.out.println(i);
        }

        output.close();
    }

}


ReadInts:

import java.io.DataInputStream;
import java.io.FileInputStream;
import java.io.IOException;

public class ReadInts {
    public static void main(String[] args) throws IOException {
        DataInputStream input = new DataInputStream(new FileInputStream(
                "data.dat"));

        while (input.available() > 0) {
            int x = input.readInt();
            System.out.println(x);
        }

        input.close();
    }

}

08-06 11:41