我想从一个称为RMA的表中进行选择(简化):

 idRMA| RMA_Number
 -----------------------
 1      RMA0006701
 2      RMA0006730
 3      RMA0006736
 4      RMA0006739
 5      RMA0006742
RMAtdefSymptomCode之间有一个连接表,称为trelRMA_SymptomCode:
 fiSymptomCode| fiRMA
 -----------------------
 1              1
 1              2
 2              2
 5              3
 7              3
 8              3
 2              5
 3              5
 4              5
 5              5

为了完整起见,这是tdefSymptomCode:
idSymptomCode    SymptomCodeNumber      SymptomCodeName
1                0000                   Audio problem
2                0100                   SIM problem
3                0200                   Appearance problem
4                0300                   Network problem
5                0500                   On/Off problem

问:

每个RMA可以具有0-5个症状代码。如何在标量值函数中将带有':'之类的分隔符的SymptomCodeNumber连接在一起,这样我只能得到一个varchar值。

像这样的东西(其中getRmaSymptomCodes是SVF):
SELECT idRMA, RMA_Number, dbo.getRmaSymptomCodes(idRMA,':') AS Symptoms FROM RMA

这可能是3种不同RMA的症状(均具有一种症状):
RMA_Number    SymptomCodeNumber
RMA0004823    0100
RMA0004823    0200
RMA0000083    0300
RMA0000084    0300
RMA0000084    0400

应将其串联为:
RMA0004823    0100:0200
RMA0000083    0300
RMA0000084    0300:0400

先感谢您

更新:多亏我创建了这个工作功能
CREATE FUNCTION [dbo].[getRmaSymptomCodes]
(
    @idRMA int,
    @delimiter varchar(5)
)
RETURNS VARCHAR(8000)
AS
BEGIN
    DECLARE @Codes VARCHAR(8000)
    SELECT @Codes = COALESCE(@Codes + @delimiter, '') +  tdefSymptomCode.SymptomCodeNumber
    FROM  RMA INNER JOIN
        trelRMA_SymptomCode ON RMA.IdRMA = trelRMA_SymptomCode.fiRMA INNER JOIN
        tdefSymptomCode ON trelRMA_SymptomCode.fiSymptomCode = tdefSymptomCode.idSymptomCode
    where idRMA=@idRMA
    order by SymptomCodeNumber
    return @Codes
END

最佳答案

这样可以吗?

DECLARE @Codes VARCHAR(8000)
SELECT @Codes = COALESCE(@Codes + ', ': '') +  tdefSymptomCode.SymptomCodeNumber
    FROM  RMA INNER JOIN
        trelRMA_SymptomCode ON RMA.IdRMA = trelRMA_SymptomCode.fiRMA INNER JOIN
        tdefSymptomCode ON trelRMA_SymptomCode.fiSymptomCode = tdefSymptomCode.idSymptomCode
    where idRMA=2
    order by SymptomCodeNumber
return @Codes

10-04 19:29