我正在创建一个加载图像的项目，并将其转换为1和零，然后使用乌龟绘制此图像。但是，每次运行时，它告诉我在第一列完成之后它已经停止工作。如果问题出在我计算机的处理能力上，我想知道是否有一种方法可以切换到GPU来完成任务。任何帮助将不胜感激。谢谢
def ShowMaze(possibleRoutes):
turtle.delay(0)
for x in range(0,len(Maze)):
for y in range(0,len(Maze[0])):
if Maze[x][y]==3:
Maze[x][y]=0
for x in range(0,len(Maze)):
turtle.forward(-5)
turtle.right(90)
turtle.forward(5/len(Maze[0]))
turtle.left(90)
for y in range(0,len(Maze[0])):
if Maze[x][y]==1:
turtle.fillcolor("black")
turtle.begin_fill()
elif Maze[x][y]==0:
turtle.fillcolor("white")
turtle.begin_fill()
elif Maze[x][y]==4:
turtle.fillcolor("green")
turtle.begin_fill()
elif Maze[x][y]==5:
turtle.fillcolor("red")
turtle.begin_fill()
for i in range(0,4):
turtle.forward(5/len(Maze[0]))
turtle.left(90)
turtle.end_fill()
turtle.forward(5/len(Maze[0]))
input()
for ii in range(1,len(possibleRoutes)-1):
turtle.pu()
turtle.home()
turtle.forward(-250)
turtle.forward((250/len(Maze))*possibleRoutes[ii][1])
turtle.right(90)
turtle.forward((250/len(Maze))*possibleRoutes[ii][0]+(250/len(Maze)))
turtle.left(90)
turtle.fillcolor("blue")
turtle.pd()
turtle.begin_fill()
for x in range(0,4):
turtle.forward(250/len(Maze[0]))
turtle.left(90)
turtle.end_fill()
im = Image.open('D:/MazeSolver/ExampleMazePicture.JPG') # Can be many different formats.
pix = im.load()
size=250
Maze=[]
length=im.size[0] # Get the width and hight of the Maze for iterating over
for x in range(0,size,8):
print("Row",x)
row=[]
for y in range(0,size,2):
pix = im.load()
if pix[x,y]>=(200,200,200):
node=0
elif pix[x,y][0]>200 and pix[x,y][2]<200 and pix[x,y][1]<200:
node=4
print("End")
elif pix[x,y][1]>200 and pix[x,y][0]<50 and pix[x,y][2]<50:
node=5
print("Start")
elif pix[x,y]<=(50,50,50):
node=1
else:
print(pix[x,y])
row.append(node)
Maze.append([row])
ShowMaze(Maze)
最佳答案
这段代码是一团糟。您将一个名为Maze的JPEG迷宫图像输入到二维数组中，并将其传递给ShowMaze(Maze)以表明您已正确阅读它。但是ShowMaze()全局访问Maze并认为其参数是ShowMaze(possibleRoutes)，其中从未计算过迷宫中的possibleRoutes吗？另外：Maze的X和Y感觉似乎颠倒了；迷宫的各行没有明显的原因在它们周围包裹了一层额外的list层；其中包含无效代码；您不是以1和0的形式阅读它，而是以四种不同的颜色代码阅读；绘图代码似乎毫无希望。
我已经对您的代码进行了重新设计，以将迷宫简单地读取到列表列表中，然后使用图章（而不是通过绘图）与乌龟一起显示它，从而简化并加速了代码：
from turtle import Screen, Turtle
from PIL import Image
CURSOR_SIZE = 20
PIXEL_SIZE = 5
COLORS = {0: 'white', 1: 'black', 4: 'green', 5: 'red'}
def ShowMaze(maze):
height, width = len(maze), len(maze[0])
screen = Screen()
screen.setup(width * PIXEL_SIZE, height * PIXEL_SIZE)
screen.setworldcoordinates(0, height, width, 0)
turtle = Turtle('square', visible=False)
turtle.shapesize(PIXEL_SIZE / CURSOR_SIZE)
turtle.penup()
screen.tracer(False)
for y in range(height):
for x in range(width):
color = maze[y][x]
if color in COLORS:
turtle.fillcolor(COLORS[color])
else:
turtle.fillcolor("orange") # error color
turtle.stamp()
turtle.forward(1)
turtle.goto(0, turtle.ycor() + 1)
screen.tracer(True)
screen.mainloop()
image = Image.open('ExampleMazePicture.JPG') # Can be many different formats.
width, height = image.size # Get the width and height of the Maze for iterating over
pixels = image.load()
maze = []
for y in range(0, width, 4):
print("Row:", y)
row = []
for x in range(0, width, 4):
node = -1
pixel = pixels[x, y]
if pixel >= (200, 200, 200):
node = 0
elif pixel[0] > 200 and pixel[1] < 200 and pixel[2] < 200:
node = 4
print("End")
elif pixel[0] < 50 and pixel[1] > 200 and pixel[2] < 50:
node = 5
print("Start")
elif pixel <= (50, 50, 50):
node = 1
else:
print(pixel)
row.append(node)
maze.append(row)
ShowMaze(maze)
基于使用"Figure 1.6: Picobot’s maze." from this page作为输入的输出：
希望这可以为您最终尝试开发的程序提供一个起点。
关于python - 运行代码时，Turtle图形脚本不断崩溃，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/54599912/