我正在尝试同时显示2个随机骰子。我知道我需要将模具编号转换为资源ID,但如何?这是我到目前为止的代码...
有什么好的编码方式?
void CMFCApplication5Dlg::OnBnClickedButton1()
{
// randomize random number generator using current time
srand( (unsigned)time( NULL ) );
// pick random die values
int die1 = 1 + rand() % 6; // first die roll
int die2 = 1 + rand() % 6; // second die roll
pPCAvatar = (CStatic *) GetDlgItem(PC_AVATAR);
pIDCPicture = (CStatic *) GetDlgItem(IDC_PICTURE2);
//image for the avatar
CString Image1;
CString Image2;
CString Image3;
CString Image4;
CString Image5;
CString Image6;
//initialize entity from the constructor
Image1 = "pcture1.bmp"; // die face # 1
Image2 = "pcture2.bmp"; // die face # 2
Image3 = "pcture3.bmp"; // die face # 3
Image4 = "pcture4.bmp"; // die face # 4
Image5 = "pcture5.bmp"; // die face # 5
Image6 = "pcture6.bmp"; // die face # 6
// TODO: Add your control notification handler code here
}
最佳答案
一种方法是使用switch/case
语句。
CString dieImage;
switch(dieValue)
{
case 0:
dieImage = "filename1";
break;
case 1:
dieImage = "filename2";
break;
// Rest of case statements
}
另一种方法是使用数组。
const CString dieImages[6] =
{
"filename1",
"filename2",
"filename3",
"filename4",
"filename5",
"filename6"
};
const CString& dieImage = dieImages[dieValue];
如果要使用多个值,可以将其放入函数并将数组设为静态成员变量
const CString& GetDieImage(int dieValue) const
{
return dieImages[dieValue];
}
只是这样称呼它
const CString& dieImage1 = GetDieImage(dieValue1);
const CString& dieImage2 = GetDieImage(dieValue2);
要使用数组来管理图像名称,您可以将代码更改为如下所示。
void CMFCApplication5Dlg::OnBnClickedButton1()
{
static const CString dieImages[6] =
{
"filename1",
"filename2",
"filename3",
"filename4",
"filename5",
"filename6"
};
// pick random die values
const int die1 = 1 + rand() % 6; // first die roll
const int die2 = 1 + rand() % 6; // second die roll
const CString die1image = dieImages[die1];
const CString die2image = dieImages[die2];
// ... rest of your code goes here ...
}
关于c++ - 随机位图将数字转换为资源ID,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/16247799/