我试图使我的Pedestrian
对象移动,并且它移动了,但是在特定点它飞离了屏幕。 Pedestrian
移动List
点。首先将Pedestrian
添加到toDraw
进行绘画,然后在startAndCreateTimer
中循环浏览同一列表以移动Vehicles
也许是因为i = (double) diff / (double) playTime;
这一行我实际上不想设置播放时间如何不这样做,这可能是问题还是其他原因?此处的链接指向Pedestrian
飞离点(从左回旋处以北开始)http://gyazo.com/23171a6106c88f1ba8ca438598ff4153。
class Surface extends JPanel{
Track track=new Track();
public List<Vehicle> toDraw = new ArrayList<>();
private Long startTime;
private long playTime = 4000;
private double i;
public Surface(){
startAndCreateTimer();
}
@Override
public void paintComponent(Graphics g) {
super.paintComponent(g);
//Make sure the track is painted first
track.paint(g);
for (Vehicle v : toDraw) {
v.paint(g);
}
}
public void repaintPanel(){
this.repaint();
}
private void startAndCreateTimer(){
Timer timer = new Timer(100, new ActionListener() {
@Override
public void actionPerformed(ActionEvent e) {
if (startTime == null) {
startTime = System.currentTimeMillis();
}
long now = System.currentTimeMillis();
long diff = now - startTime;
i = (double) diff / (double) playTime;
for (Vehicle v : toDraw){
v.update(i);
}
repaintPanel();
}
});
timer.start();
}
}
行人爪哇
public class Pedestrian extends Vehicle {
BufferedImage pedestrian;
Point pedestrianPosition;
double pedestrianRotation = 0;
int pedestrianW, pedestrianH;
int counter=0;
List<LanePoint>pedestrianPath;
boolean lockCounter=false;
public Pedestrian(int x, int y){
try {
pedestrian = ImageIO.read(Car.class.getResource("images/human.png"));
} catch (IOException e) {
System.out.println("Problem loading pedestrian images: " + e);
}
pedestrianPosition = new Point(x,y);
pedestrianW = pedestrian.getWidth();
pedestrianH = pedestrian.getHeight();
}
@Override
public void paint(Graphics g) {
Graphics2D g2d = (Graphics2D) g.create();
g2d.rotate(Math.toRadians(pedestrianRotation), pedestrianPosition.x, pedestrianPosition.y);
g2d.drawImage(pedestrian, pedestrianPosition.x, pedestrianPosition.y, null);
}
@Override
public void setPath(List<LanePoint> path) {
pedestrianPath=path;
}
/*Update*/
@Override
public void update(double i){
if (counter < pedestrianPath.size()) {
Point startPoint = new Point(pedestrianPosition.x, pedestrianPosition.y);
LanePoint endPoint = new LanePoint(pedestrianPath.get(counter).x, pedestrianPath.get(counter).y,pedestrianPath.get(counter).lanePointType,pedestrianPath.get(counter).lanePointToTrafficLight,pedestrianPath.get(counter).laneTrafficLightId,pedestrianPath.get(counter).degreesRotation);
pedestrianPosition.x=(int)Maths.lerp(startPoint.x,endPoint.x,i);
pedestrianPosition.y=(int)Maths.lerp(startPoint.y,endPoint.y,i);
pedestrianRotation=endPoint.degreesRotation;
if(pedestrianPosition.equals(new Point(endPoint.x,endPoint.y))){
/*PEDESTRIAN SIGN UP*/
if (endPoint.lanePointType.equals(LanePoint.PointType.TRAFFICLIGHT) && endPoint.lanePointToTrafficLight.equals(LanePoint.PointToTrafficLight.INFRONTOF)){
try {
Roundabout.client.sendBytes(new byte []{0x03,endPoint.laneTrafficLightId.byteValue(),0x01,0x00});
} catch (IOException ex) {
ex.printStackTrace();
}
}
/*PEDESTRIAN SIGN OFF*/
else if (endPoint.lanePointType.equals(LanePoint.PointType.TRAFFICLIGHT) && endPoint.lanePointToTrafficLight.equals(LanePoint.PointToTrafficLight.UNDERNEATH)) {
if (Surface.trafficLights.get(endPoint.laneTrafficLightId).red) {
lockCounter = true;
} else {
try {
Roundabout.client.sendBytes(new byte[]{0x03, endPoint.laneTrafficLightId.byteValue(), 0x00, 0x00});
lockCounter=false;
} catch (IOException ex) {
ex.printStackTrace();
}
}
}
if (!lockCounter) {
counter++; //Increment counter > sets next point
}
}
}
}
}
Maths.java
public class Maths {
//Lineat interpolation
public static double lerp(double a, double b, double t) {
return a + (b - a) * t;
}
}
最佳答案
因此,基本上,您是根据经过的时间来计算对象与点之间的位置。很好
因此,在t = 0
处,对象将位于起点处,在t = 0.5
处,它将位于起点和终点之间的中间,在t = 1.0
处,它将位于终点处。t > 1.0
会发生什么?对象应该在哪里? -提示,应该不存在,因为它应该已被删除或重置...
This和this是基于“时间线”的动画的基本示例,这意味着在一段时间内,通过使用不同的点(沿着时间线)确定对象的位置
因此,为了计算沿一条线的位置,您需要三件事:您开始的位置,您要结束的位置以及持续时间(0-1之间)
使用这些,您可以基于时间量来计算这两点之间的直线上的点。
import java.awt.Color;
import java.awt.Dimension;
import java.awt.EventQueue;
import java.awt.Graphics;
import java.awt.Graphics2D;
import java.awt.Point;
import java.awt.event.ActionEvent;
import java.awt.event.ActionListener;
import java.awt.geom.Ellipse2D;
import java.awt.geom.Line2D;
import java.awt.geom.Point2D;
import javax.swing.JFrame;
import javax.swing.JPanel;
import javax.swing.Timer;
import javax.swing.UIManager;
import javax.swing.UnsupportedLookAndFeelException;
public class Test {
public static void main(String[] args) {
new Test();
}
public Test() {
EventQueue.invokeLater(new Runnable() {
@Override
public void run() {
try {
UIManager.setLookAndFeel(UIManager.getSystemLookAndFeelClassName());
} catch (ClassNotFoundException | InstantiationException | IllegalAccessException | UnsupportedLookAndFeelException ex) {
ex.printStackTrace();
}
JFrame frame = new JFrame("Testing");
frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
frame.add(new TestPane());
frame.pack();
frame.setLocationRelativeTo(null);
frame.setVisible(true);
}
});
}
public static class TestPane extends JPanel {
protected static final double PLAY_TIME = 4000.0;
private Point2D startAt = new Point(0, 0);
private Point2D endAt = new Point(200, 200);
private Point2D current = startAt;
private Long startTime;
public TestPane() {
Timer timer = new Timer(40, new ActionListener() {
@Override
public void actionPerformed(ActionEvent e) {
if (startTime == null) {
startTime = System.currentTimeMillis();
}
long time = System.currentTimeMillis() - startTime;
double percent = (double) time / PLAY_TIME;
if (percent > 1.0) {
percent = 1.0;
((Timer) e.getSource()).stop();
}
current = calculateProgress(startAt, endAt, percent);
repaint();
}
});
timer.start();
}
protected Point2D calculateProgress(Point2D startPoint, Point2D targetPoint, double progress) {
Point2D point = new Point2D.Double();
if (startPoint != null && targetPoint != null) {
point.setLocation(
calculateProgress(startPoint.getX(), targetPoint.getY(), progress),
calculateProgress(startPoint.getX(), targetPoint.getY(), progress));
}
return point;
}
protected double calculateProgress(double startValue, double endValue, double fraction) {
return startValue + ((endValue - startValue) * fraction);
}
@Override
public Dimension getPreferredSize() {
return new Dimension(200, 200);
}
@Override
protected void paintComponent(Graphics g) {
super.paintComponent(g);
Graphics2D g2d = (Graphics2D) g.create();
g2d.setColor(Color.GREEN);
g2d.draw(new Line2D.Double(startAt, endAt));
g2d.setColor(Color.RED);
g2d.fill(new Ellipse2D.Double(current.getX() - 5, current.getY() - 5, 10, 10));
g2d.dispose();
}
}
}
因此,使用
current = calculateProgress(startAt, endAt, percent);
您会看到点在起点和终点之间均匀移动。
如果我们将其更改为更像您正在执行的操作,
current = calculateProgress(current, endAt, percent);
,您会看到它加快了速度并最终减轻了负担,这不是您真正想要的...
更新了时间轴理论
假设您有一个时间轴,其长度为
t
,并且沿着该时间轴,您有5个事件(或关键帧)(e1
-e5
),每个事件彼此之间发生。e1
开始于0
,e5
结束于1
如您所见,事件以不规则的间隔发生,并运行不同的时间长度。
t1运行时间轴的25%
t2运行时间轴的25%
t3运行时间线的12.5%
t3运行时间轴的37.5%
因此,基于
t
,您需要确定执行了哪些事件。因此,当t
为0.12
时,我们大约要经过t1
的一半(在e1和e2之间)。然后,您需要计算关键帧之间的本地时间/差异(沿时间轴的0-0.25)
localTime = 1.0 - ((t - e1) / (e2 - e1))
= 1.0 - ((0.12 - 0) / (0.25 - 0))
= 1.0 - (0.12 / 0.25)
= 1.0 - 0.48
= 0.52
其中
t
是沿时间线的时间,e1
是第一个事件的时间(0
),而e2
是第二个事件的时间(0.25
),这提供了持续时间t1
(在此示例中)这就是给定时间片的线性插值的值。
可运行的示例...
我看了看您的代码,但是要使它正常工作,需要做很多工作。
基本上,您需要知道路径的长度以及该路径的每个段的数量(以百分比为单位)。这样,我们可以创建一个“关键帧”的“时间线”,该时间线根据经过的时间量和“应该”移动的时间量来确定对象沿“路径”走的距离。
因此,我要做的第一件事是创建一个
Path
类(类似于您的List
,但具有一些其他方法)public class Path implements Iterable<Point> {
private List<Point> points;
private double totalLength = 0;
public Path(Point... points) {
this.points = new ArrayList<>(Arrays.asList(points));
for (int index = 0; index < size() - 1; index++) {
Point a = get(index);
Point b = get(index + 1);
double length = lengthBetween(a, b);
totalLength += length;
}
}
public double getTotalLength() {
return totalLength;
}
public int size() {
return points.size();
}
public Point get(int index) {
return points.get(index);
}
public double lengthBetween(Point a, Point b) {
return Math.sqrt(
(a.getX() - b.getX()) * (a.getX() - b.getX())
+ (a.getY() - b.getY()) * (a.getY() - b.getY()));
}
@Override
public Iterator<Point> iterator() {
return points.iterator();
}
}
通常,这提供了路径的
totalLength
。我们用它来计算每个段以后要占用多少然后,我从this先前的答案中借用了
TimeLine
类public class Timeline {
private Map<Double, KeyFrame> mapEvents;
public Timeline() {
mapEvents = new TreeMap<>();
}
public void add(double progress, Point p) {
mapEvents.put(progress, new KeyFrame(progress, p));
}
public Point getPointAt(double progress) {
if (progress < 0) {
progress = 0;
} else if (progress > 1) {
progress = 1;
}
KeyFrame[] keyFrames = getKeyFramesBetween(progress);
double max = keyFrames[1].progress - keyFrames[0].progress;
double value = progress - keyFrames[0].progress;
double weight = value / max;
return blend(keyFrames[0].getPoint(), keyFrames[1].getPoint(), 1f - weight);
}
public KeyFrame[] getKeyFramesBetween(double progress) {
KeyFrame[] frames = new KeyFrame[2];
int startAt = 0;
Double[] keyFrames = mapEvents.keySet().toArray(new Double[mapEvents.size()]);
while (startAt < keyFrames.length && keyFrames[startAt] <= progress) {
startAt++;
}
if (startAt >= keyFrames.length) {
startAt = keyFrames.length - 1;
}
frames[0] = mapEvents.get(keyFrames[startAt - 1]);
frames[1] = mapEvents.get(keyFrames[startAt]);
return frames;
}
protected Point blend(Point start, Point end, double ratio) {
Point blend = new Point();
double ir = (float) 1.0 - ratio;
blend.x = (int) (start.x * ratio + end.x * ir);
blend.y = (int) (start.y * ratio + end.y * ir);
return blend;
}
public class KeyFrame {
private double progress;
private Point point;
public KeyFrame(double progress, Point point) {
this.progress = progress;
this.point = point;
}
public double getProgress() {
return progress;
}
public Point getPoint() {
return point;
}
}
}
现在,按照它们的立场来看,它们是不兼容的,我们需要获取每个分段并将分段的长度计算为路径总长度的百分比,然后沿着时间轴为指定点创建关键帧...
double totalLength = path.getTotalLength();
timeLine = new Timeline();
timeLine.add(0, path.get(0));
// Point on time line...
double potl = 0;
for (int index = 1; index < path.size(); index++) {
Point a = path.get(index - 1);
Point b = path.get(index);
double length = path.lengthBetween(a, b);
double normalised = length / totalLength;
// Normalised gives as the percentage of this segment, we need to
// translate that to a point on the time line, so we just add
// it to the "point on time line" value to move to the next point :)
potl += normalised;
timeLine.add(potl, b);
}
我故意这样做,以展示您需要做的工作。
需要,我创建一个
Ticker
,它仅运行Swing Timer
并将tick
s报告给Animation
public enum Ticker {
INSTANCE;
private Timer timer;
private List<Animation> animations;
private Ticker() {
animations = new ArrayList<>(25);
timer = new Timer(5, new ActionListener() {
@Override
public void actionPerformed(ActionEvent e) {
// Prevent possible mutatation issues...
Animation[] anims = animations.toArray(new Animation[animations.size()]);
for (Animation animation : anims) {
animation.tick();
}
}
});
}
public void add(Animation animation) {
animations.add(animation);
}
public void remove(Animation animation) {
animations.remove(animation);
}
public void start() {
timer.start();
}
public void stop() {
timer.stop();
}
}
public interface Animation {
public void tick();
}
这将集中“时钟”,允许
Animation
确定在每个tick
上要执行的操作。这应该更具可扩展性,然后创建数十个Timer
好的,这很有趣,也很有趣,但是如何一起工作呢?好吧,这是一个完整的可运行示例。
它采用您自己的路径之一,并在其中创建一个
TimeLine
并为沿该对象移动的对象设置动画。import java.awt.Color;
import java.awt.Dimension;
import java.awt.EventQueue;
import java.awt.Graphics;
import java.awt.Graphics2D;
import java.awt.Point;
import java.awt.event.ActionEvent;
import java.awt.event.ActionListener;
import java.awt.geom.Ellipse2D;
import java.awt.geom.Path2D;
import java.text.NumberFormat;
import java.util.ArrayList;
import java.util.Arrays;
import java.util.Iterator;
import java.util.List;
import java.util.Map;
import java.util.TreeMap;
import javax.swing.JFrame;
import javax.swing.JPanel;
import javax.swing.Timer;
import javax.swing.UIManager;
import javax.swing.UnsupportedLookAndFeelException;
public class Test {
public static void main(String[] args) {
new Test();
}
public Test() {
EventQueue.invokeLater(new Runnable() {
@Override
public void run() {
try {
UIManager.setLookAndFeel(UIManager.getSystemLookAndFeelClassName());
} catch (ClassNotFoundException | InstantiationException | IllegalAccessException | UnsupportedLookAndFeelException ex) {
ex.printStackTrace();
}
Path path = new Path(
new Point(440, 40),
new Point(440, 120),
new Point(465, 90),
new Point(600, 180),
new Point(940, 165),
new Point(940, 145),
new Point(1045, 105),
new Point(1080, 120),
new Point(1170, 120),
new Point(1200, 120),
new Point(1360, 123),
new Point(1365, 135),
new Point(1450, 170),
new Point(1457, 160),
new Point(1557, 160));
JFrame frame = new JFrame("Testing");
frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
frame.add(new TestPane(path));
frame.pack();
frame.setLocationRelativeTo(null);
frame.setVisible(true);
Ticker.INSTANCE.start();
}
});
}
public enum Ticker {
INSTANCE;
private Timer timer;
private List<Animation> animations;
private Ticker() {
animations = new ArrayList<>(25);
timer = new Timer(5, new ActionListener() {
@Override
public void actionPerformed(ActionEvent e) {
// Prevent possible mutatation issues...
Animation[] anims = animations.toArray(new Animation[animations.size()]);
for (Animation animation : anims) {
animation.tick();
}
}
});
}
public void add(Animation animation) {
animations.add(animation);
}
public void remove(Animation animation) {
animations.remove(animation);
}
public void start() {
timer.start();
}
public void stop() {
timer.stop();
}
}
public interface Animation {
public void tick();
}
public static final double PLAY_TIME = 4000d;
public class TestPane extends JPanel implements Animation {
private Path path;
private Path2D pathShape;
private Timeline timeLine;
private Long startTime;
private Point currentPoint;
public TestPane(Path path) {
this.path = path;
// Build the "path" shape, we can render this, but more importantally
// it allows use to determine the preferred size of the panel :P
pathShape = new Path2D.Double();
pathShape.moveTo(path.get(0).x, path.get(0).y);
for (int index = 1; index < path.size(); index++) {
Point p = path.get(index);
pathShape.lineTo(p.x, p.y);
}
// Build the time line. Each segemnt (the line between any two points)
// makes up a percentage of the time travelled, we need to calculate
// the amount of time that it would take to travel that segement as
// a percentage of the overall length of the path...this
// allows us to even out the time...
double totalLength = path.getTotalLength();
timeLine = new Timeline();
timeLine.add(0, path.get(0));
// Point on time line...
double potl = 0;
for (int index = 1; index < path.size(); index++) {
Point a = path.get(index - 1);
Point b = path.get(index);
double length = path.lengthBetween(a, b);
double normalised = length / totalLength;
// Normalised gives as the percentage of this segment, we need to
// translate that to a point on the time line, so we just add
// it to the "point on time line" value to move to the next point :)
potl += normalised;
timeLine.add(potl, b);
}
currentPoint = path.get(0);
Ticker.INSTANCE.add(this);
}
@Override
public Dimension getPreferredSize() {
Dimension size = pathShape.getBounds().getSize();
size.width += pathShape.getBounds().x;
size.height += pathShape.getBounds().y;
return size;
}
@Override
protected void paintComponent(Graphics g) {
super.paintComponent(g);
Graphics2D g2d = (Graphics2D) g.create();
g2d.setColor(Color.GREEN);
g2d.draw(pathShape);
g2d.setColor(Color.RED);
g2d.fill(new Ellipse2D.Double(currentPoint.x - 5, currentPoint.y - 5, 10, 10));
g2d.dispose();
}
@Override
public void tick() {
if (startTime == null) {
startTime = System.currentTimeMillis();
}
long diff = System.currentTimeMillis() - startTime;
double t = (double)diff / PLAY_TIME;
if (t > 1.0) {
t = 1.0d;
// Don't call me any more, I'm already home
Ticker.INSTANCE.remove(this);
}
currentPoint = timeLine.getPointAt(t);
repaint();
}
}
public class Path implements Iterable<Point> {
private List<Point> points;
private double totalLength = 0;
public Path(Point... points) {
this.points = new ArrayList<>(Arrays.asList(points));
for (int index = 0; index < size() - 1; index++) {
Point a = get(index);
Point b = get(index + 1);
double length = lengthBetween(a, b);
totalLength += length;
}
}
public double getTotalLength() {
return totalLength;
}
public int size() {
return points.size();
}
public Point get(int index) {
return points.get(index);
}
public double lengthBetween(Point a, Point b) {
return Math.sqrt(
(a.getX() - b.getX()) * (a.getX() - b.getX())
+ (a.getY() - b.getY()) * (a.getY() - b.getY()));
}
@Override
public Iterator<Point> iterator() {
return points.iterator();
}
}
public class Timeline {
private Map<Double, KeyFrame> mapEvents;
public Timeline() {
mapEvents = new TreeMap<>();
}
public void add(double progress, Point p) {
mapEvents.put(progress, new KeyFrame(progress, p));
}
public Point getPointAt(double progress) {
if (progress < 0) {
progress = 0;
} else if (progress > 1) {
progress = 1;
}
KeyFrame[] keyFrames = getKeyFramesBetween(progress);
double max = keyFrames[1].progress - keyFrames[0].progress;
double value = progress - keyFrames[0].progress;
double weight = value / max;
return blend(keyFrames[0].getPoint(), keyFrames[1].getPoint(), 1f - weight);
}
public KeyFrame[] getKeyFramesBetween(double progress) {
KeyFrame[] frames = new KeyFrame[2];
int startAt = 0;
Double[] keyFrames = mapEvents.keySet().toArray(new Double[mapEvents.size()]);
while (startAt < keyFrames.length && keyFrames[startAt] <= progress) {
startAt++;
}
if (startAt >= keyFrames.length) {
startAt = keyFrames.length - 1;
}
frames[0] = mapEvents.get(keyFrames[startAt - 1]);
frames[1] = mapEvents.get(keyFrames[startAt]);
return frames;
}
protected Point blend(Point start, Point end, double ratio) {
Point blend = new Point();
double ir = (float) 1.0 - ratio;
blend.x = (int) (start.x * ratio + end.x * ir);
blend.y = (int) (start.y * ratio + end.y * ir);
return blend;
}
public class KeyFrame {
private double progress;
private Point point;
public KeyFrame(double progress, Point point) {
this.progress = progress;
this.point = point;
}
public double getProgress() {
return progress;
}
public Point getPoint() {
return point;
}
}
}
}
现在,如果要执行此操作,则可以在
Path
中或作为static
实用程序方法创建一个方法,该方法采用Path
并自动返回TimeLine
;)