ios - 如何使用URL Shema将UIImage共享到Instagram应用？

我有创建的图像，想通过instagram应用程序共享它，该怎么办？

 - (IBAction)instagramShareTapped:(UIButton *)sender {
   UIImage *img = self.myImage;
   NSURL *instagramURL = [NSURL URLWithString:[NSString stringWithFormat:@"instagram://**WHAT_SHOULD_I_PUT_HERE?**]];
   if ([[UIApplication sharedApplication] canOpenURL:instagramURL]) {
     [[UIApplication sharedApplication] openURL:instagramURL];
   }
}

最佳答案

这是我可以使用URL架构将UIImage共享到Instagram的方法:

    ALAssetsLibrary *library = [[ALAssetsLibrary alloc] init];
    UIImage *image = // your image that you want share
    [library writeImageToSavedPhotosAlbum:image.CGImage orientation:(ALAssetOrientation)image.imageOrientation completionBlock:^(NSURL *assetURL, NSError *error) {

      NSString *escapedString = [assetURL.absoluteString stringByAddingPercentEncodingWithAllowedCharacters:[NSCharacterSet alphanumericCharacterSet]];
      NSURL *instagramURL = [NSURL URLWithString:[NSString stringWithFormat:@"instagram://library?AssetPath=%@", escapedString]];

      if ([[UIApplication sharedApplication] canOpenURL:instagramURL]) {
        [[UIApplication sharedApplication] openURL:instagramURL];
      } else {
        NSLog(@"Instagram app not found.");
      }
    }];