python - Python 3和Pocket Sphinx

我正在尝试为我的祖父创建一个简单的音乐播放器，该祖父通过对音频控制的音乐播放器进行编程来解决按钮问题。我正在使用带有Python 3和Pocket Sphinx的Raspberry Pi 3。因为Pocket Sphinx不需要Internet，所以我将使用它，因为我的祖父无法访问Internet。

我的问题是如何获取“said”的值，例如:“播放按钮”并让其播放波形文件“按钮”？

这是我必须构建的基本程序:

import speech_recognition as sr
import pygame
from pygame import mixer
mixer.init()

r = sr.Recognizer()
m = sr.Microphone()

Button = pygame.mixer.Sound('/home/pi/Downloads/button8.wav')

try:
    print("A moment of silence, please...")
    with m as source: r.adjust_for_ambient_noise(source)
    print("Set minimum energy threshold to {}".format(r.energy_threshold))
    while True:
        print("Say something!")
        with m as source: audio = r.listen(source)
        print("Got it! Now to recognize it...")
        try:
            # recognize speech using Sphinx
            value = r.recognize_sphinx(audio)
            print("You said {}".format(value)) #uses unicode for strings and this is where I am stuck
            pygame.mixer.Sound.play(Button)
            pygame.mixer.music.stop()
        except sr.UnknownValueError:
            print("Oops! Didn't catch that")
        except sr.RequestError as e:
            print("Uh oh! Couldn't request results; {0}".format(e))
except KeyboardInterrupt:
    pass

非常感谢您提供的任何帮助。请好心，因为我是初学者。

最佳答案

尝试将其与“播放按钮”进行比较:

# recognize speech using Sphinx
value = r.recognize_sphinx(audio)
print("You said {}".format(value))

if value.lower() == 'play button':
    pygame.mixer.Sound.play(Button)
    pygame.mixer.music.stop()