我目前正在用C++(使用crypto ++)编写河豚加密/解密程序。
我真的在Google上找不到满意的答案。我正在尝试将SecByteBlock的密钥作为字符串发送,然后在另一部分作为字符串接收,然后需要重新获取到SecByteBlock。
是否可以转换字符串 SecByteBlock
我可以做些更好的事情来将密钥从一个功能发送到另一个功能吗?
预先感谢您的帮助。
我使用的代码如下:
int main(int argc, char* argv[])
{
AutoSeededRandomPool prng;
SecByteBlock key(Blowfish::DEFAULT_KEYLENGTH);
prng.GenerateBlock(key, key.size());
byte iv[Blowfish::BLOCKSIZE];
prng.GenerateBlock(iv, sizeof(iv));
BLOCK test = ReadStaticBlocks("testBin.dat");
string plain=test.bl1 ;
string cipher, encoded, recovered;
/*********************************\
\*********************************/
// Pretty print key
encoded.clear();
StringSource ss1(key, key.size(), true,
new HexEncoder(
new StringSink(encoded)
) // HexEncoder
); // StringSource
cout << "key: " << encoded << endl;
// Pretty print iv
encoded.clear();
StringSource ss2(iv, sizeof(iv), true,
new HexEncoder(
new StringSink(encoded)
) // HexEncoder
); // StringSource
cout << "iv: " << encoded << endl;
/*********************************\
\*********************************/
try
{
cout << "plain text: " << plain << endl;
CBC_Mode< Blowfish >::Encryption e;
e.SetKeyWithIV(key, key.size(), iv);
// The StreamTransformationFilter adds padding
// as required. ECB and CBC Mode must be padded
// to the block size of the cipher.
StringSource ss3(plain, true,
new StreamTransformationFilter(e,
new StringSink(cipher)
) // StreamTransformationFilter
); // StringSource
}
catch(const CryptoPP::Exception& e)
{
cerr << e.what() << endl;
exit(1);
}
/*********************************\
\*********************************/
// Pretty print
encoded.clear();
StringSource ss4(cipher, true,
new HexEncoder(
new StringSink(encoded)
) // HexEncoder
); // StringSource
cout << "cipher text: " << encoded << endl;
/*********************************\
\*********************************/
try
{
CBC_Mode< Blowfish >::Decryption d;
d.SetKeyWithIV(key, key.size(), iv);
// The StreamTransformationFilter removes
// padding as required.
StringSource ss5(cipher, true,
new StreamTransformationFilter(d,
new StringSink(recovered)
) // StreamTransformationFilter
); // StringSource
cout << "recovered text: " << recovered << endl;
}
catch(const CryptoPP::Exception& e)
{
cerr << e.what() << endl;
exit(1);
}
/*********************************\
\*********************************/
system("pause");
return 0;
}
最佳答案
是。每个都有一个构造函数,该构造函数需要一个指针和一个长度。
string s1("hello world");
SecByteBlock b1((const byte*)s1.data(), s1.size());
和
byte a[] = {'h','e','l','l','o',' ','w','o','r','l','d'};
SecByteBlock b2(a, sizeof(a));
string s2((const char*)b2.data(), b2.size());
在您的情况下,
StringSource
还有一个构造函数,该构造函数需要一个指针和一个长度。因此,您可以执行:byte a[] = {'h','e','l','l','o',' ','w','o','r','l','d'};
SecByteBlock b3(a, sizeof(a));
StringSource ss1(b3.data(), b3.size(), true ...);
或更直接地:
byte a[] = {'h','e','l','l','o',' ','w','o','r','l','d'};
StringSource ss1(a, sizeof(a), true ...);