javascript - 删除集合中记录的所有重复记录-MongoDB

我有一个如下所示的mongoDB集合。如您所见，它有许多重复的记录，也许有一些不同的属性。现在，我的收藏夹中有18000个结果，我需要删除其中的所有重复项。不管我保留哪一个，我都不需要骗子。谁能帮我或指出正确的方向？ MongoDB的新手。

提前致谢

{
  commonName: "Lionel Messi",
  firstName: "Lionel",
  lastName: "Messi",
  rating: 97
},{
  commonName: "Lionel Messi",
  firstName: "Lionel",
  lastName: "Messi",
  rating: 96
},{
  commonName: "Lionel Messi",
  firstName: "Lionel",
  lastName: "Messi",
  rating: 92
},{
  commonName: "Jamie Vardy",
  firstName: "Jamie",
  lastName: "Vardy",
  rating: 82
},{
  commonName: "Jamie Vardy",
  firstName: "Jamie",
  lastName: "Vardy",
  rating: 86
}

最佳答案

您可以使用aggregate清除数据，然后使用$out编写集合，甚至覆盖当前集合：

db.players.aggregate([
  {
    $group : {
      _id : { commonName: "$commonName"  },
      commonName: {$first: "$commonName"},
      firstName: {$first: "$firstName"},
      lastName: {$first: "$lastName"},
      rating: {$first: "$rating"},
    }
  },
  { $project : { _id:0, commonName:1, firstName:1, lastName:1, rating:1 } },
  { $out : "players" }
])

注意：如果要编写新集合，请使用{ $out : "newCollection" }