python - 无法关闭KeyboardInterrupt上的套接字

from socket import socket, AF_INET, SOCK_STREAM

sock = socket(AF_INET, SOCK_STREAM)
sock.bind(("localhost", 7777))
sock.listen(1)
while True:
    try:
        connection, address = sock.accept()
        print("connected from " + address)
        received_message = sock.recv(300)
        if not received_message:
            break
        connection.sendall(b"hello")

    except KeyBoardInterrupt:
        connection.close()

所以我试图把我的头缠在套接字上，并拥有这个非常简单的脚本
但由于某些原因，我无法使用KeyboardInterrupt杀死该脚本

如何使用KeyboardInterrupt杀死脚本，为什么不能用KeyboardInterrupt杀死脚本？

最佳答案

转到break以摆脱while循环。没有break，循环将不会结束。

为了安全起见，请检查是否设置了connection。

from socket import socket, AF_INET, SOCK_STREAM

sock = socket(AF_INET, SOCK_STREAM)
sock.bind(("localhost", 7777))
sock.listen(1)
while True:
    connection = None # <---
    try:
        connection, address = sock.accept()
        print("connected from ", address)
        received_message = connection.recv(300)
        if not received_message:
            break
        connection.sendall(b"hello")
    except KeyboardInterrupt:
        if connection:  # <---
            connection.close()
        break  # <---

更新

有一个错字:KeyBoardInterrupt应该是KeyboardInterrupt。

sock.recv应该是connection.recv。