我试图使用bash
重命名目录中与特定模式匹配的所有.txt
文件。我在下面的两次尝试已从目录中删除文件并引发错误。谢谢:)
输入
16-0000_File-A_variant_strandbias_readcount.vcf.hg19_multianno_dbremoved_removed_final_index_inheritence_import.txt
16-0002_File-B_variant_strandbias_readcount.vcf.hg19_multianno_dbremoved_removed_final_index_inheritence_import.txt
期望输出
16-0000_File-A_multianno.txt
16-0002_File-B_multianno.txt
重击尝试1
this removes the files from the directory
for f in /home/cmccabe/Desktop/test/vcf/overall/annovar/*_classify.txt ; do
# Grab file prefix.
p=${f%%_*_}
bname=`basename $f`
pref=${bname%%.txt}
mv "$f" ${p}_multianno.txt
done
重击尝试2
Substitution replacement not terminated at (eval 1) line 1.
for f in /home/cmccabe/Desktop/test/vcf/overall/annovar/*_classify.txt ; do
# Grab file prefix.
p=${f%%_*_}
bname=`basename $f`
pref=${bname%%.txt}
rename -n 's/^$f/' *${p}_multianno.txt
done
最佳答案
你不需要循环。rename
只有这样才能做到:
rename -n 's/(.*?_[^_]+).*/${1}_multianno.txt/g' /home/cmccabe/Desktop/test/vcf/overall/annovar/*_classify.txt
正则表达式的含义大致是,
捕捉从开始到第二个
_
,其他的匹配,
替换为捕获的前缀并附加
_multianno.txt
使用
-n
标志时,此命令将打印它将执行的操作而不实际执行。当输出看起来良好时,删除
-n
并重新运行。关于bash - 重命名目录中特定类型的所有文件,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/42041486/