我有以下 R 数据框:
zed
# A tibble: 10 x 3
jersey_number first_name statistics.minutes
<chr> <chr> <chr>
1 20 Marques 8:20
2 53 Brennan 00:00
3 35 Marvin 40:00
4 50 Justin 00:00
5 14 Jordan 00:00
6 1 Trevon 31:00
7 15 Alex 2:00
8 51 Mike 00:00
9 12 Javin 17:00
10 3 Grayson 38:00
> dput(zed)
structure(list(jersey_number = c("20", "53", "35", "50", "14",
"1", "15", "51", "12", "3"), first_name = c("Marques", "Brennan",
"Marvin", "Justin", "Jordan", "Trevon", "Alex", "Mike", "Javin",
"Grayson"), statistics.minutes = c("8:20", "00:00", "40:00",
"00:00", "00:00", "31:00", "2:00", "00:00", "17:00", "38:00")), row.names = c(NA,
-10L), class = c("tbl_df", "tbl", "data.frame"))
这是我从 API 接收数据的格式。所有列(大约有 100 列)最初都属于
character
类。要转换所有内容,我使用 readr::type_convert()
,但发生以下错误:> zed %>% readr::type_convert()
Parsed with column specification:
cols(
jersey_number = col_integer(),
first_name = col_character(),
statistics.minutes = col_time(format = "")
)
# A tibble: 10 x 3
jersey_number first_name statistics.minutes
<int> <chr> <time>
1 20 Marques 08:20
2 53 Brennan 00:00
3 35 Marvin NA
4 50 Justin 00:00
5 14 Jordan 00:00
6 1 Trevon NA
7 15 Alex 02:00
8 51 Mike 00:00
9 12 Javin 17:00
10 3 Grayson NA
如果此分钟列改为类 == 数字,而不是抛出错误和搞乱转换,我希望它。如果该列的一行显示“8:20”,我希望将其简单地转换为 8.33。
关于如何做到这一点的任何想法 - 最好是允许我继续使用
type_convert
的东西。 最佳答案
library(lubridate)
读入 df
而不做任何改动(您的 dput
代码)。
将小时添加到分秒:
df$statistics.minutes <- paste0("00:", df$statistics.minutes)
转换为时间类型:
df$statistics.minutes <- lubridate::hms(df$statistics.minutes)
除以 60:
period_to_seconds(df$statistics.minutes) / 60
结果:
[1] 8.333333 0.000000 40.000000 0.000000 0.000000
[6] 31.000000 2.000000 0.000000 17.000000 38.000000
如果需要,替换
df
:df$statistics.minutes <- period_to_seconds(df$statistics.minutes) / 60
[ OP 的添加 ] :-)
我创建了以下辅助函数 - 基于这个结果 - 所以我可以在不破坏管道链的情况下解决问题:
fixMinutes <- function(raw.data) {
new.raw.data <- raw.data %>%
dplyr::mutate(statistics.minutes = paste0("00:", statistics.minutes)) %>%
dplyr::mutate(statistics.minutes = lubridate::hms(statistics.minutes)) %>%
dplyr::mutate(statistics.minutes = lubridate::period_to_seconds(statistics.minutes) / 60)
return(new.raw.data)
}
zed %>%
... %>%
fixMinutes() %>%
... %>%
关于readr::type_convert 弄乱了时间列,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/53982826/