public class ThreadSafe {
private int aField;
public synchronized void setAField(int value) {
aField = value;
}
public synchronized int getAField() {
return aField;
}
}
public class ThreadSafeToo {
private volatile int aField;
public synchronized void setAField(int value) {
aField = value;
}
public int getAField() {
return aField;
}
}
public class DontKnowIfThreadSafeButMostLikelyYes {
private static int aField;
public synchronized void setAField(int value) {
aField = value;
}
public int getAField() {
return aField;
}
}
问题:
DontKnowIfThreadSafeButMostLikelyYes是线程安全的吗?
首选的惯用法是什么,为什么?
最佳答案
ThreadSafeToo
不需要同步方法:volatile分配是原子的,并提供可见性保证。DontKnowIfThreadSafeButMostLikelyYes
不是线程安全的:您需要同步读取和写入共享变量。
首选惯用语是主观的,但是在您的情况下,有效的方法是:
public class ThreadSafeToo {
private volatile int aField;
public void setAField(int value) { aField = value; }
public int getAField() { return aField; }
}