我可以定义一个函数为:
def print(n:Int, s:String = "blah") {}
print: (n: Int,s: String)Unit
我可以这样称呼:
print(5)
print(5, "testing")
如果我 curry 以上:
def print2(n:Int)(s:String = "blah") {}
print2: (n: Int)(s: String)Unit
我无法使用1个参数来调用它:
print2(5)
<console>:7: error: missing arguments for method print2 in object $iw;
follow this method with `_' if you want to treat it as a partially applied function
print2(5)
我必须提供两个参数。有什么办法解决吗?
最佳答案
您不能使用默认参数忽略()
:
scala> def print2(n:Int)(s:String = "blah") {}
print2: (n: Int)(s: String)Unit
scala> print2(5)()
虽然它适用于隐式:
scala> case class SecondParam(s: String)
defined class SecondParam
scala> def print2(n:Int)(implicit s: SecondParam = SecondParam("blah")) {}
print2: (n: Int)(implicit s: SecondParam)Unit
scala> print2(5)
关于scala - 默认参数为currying,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/5074421/