我正在尝试以传递标志的方式PInvoke CreateDesktop,以通过子进程继承桌面。声明如下:

[DllImport("user32", EntryPoint = "CreateDesktopW", CharSet = CharSet.Unicode, SetLastError = true)]
        public static extern IntPtr CreateDesktop(string lpszDesktop, IntPtr lpszDevice, IntPtr pDevmode, int dwFlags,
                                                  int dwDesiredAccess, [MarshalAs(UnmanagedType.LPStruct)] SECURITY_ATTRIBUTES lpsa);

        [StructLayout(LayoutKind.Sequential)]
        public struct SECURITY_ATTRIBUTES
        {
            public int nLength;
            public IntPtr lpSecurityDescriptor;
            public int bInheritHandle;
        }


我使用它如下:

Win32.SECURITY_ATTRIBUTES sa = new Win32.SECURITY_ATTRIBUTES();
            sa.nLength = Marshal.SizeOf(sa);
            sa.bInheritHandle = 1;
            testDesktopHandle = Win32.CreateDesktop(name, IntPtr.Zero, IntPtr.Zero, 0, Win32.GENERIC_ALL, sa);


而且不幸的是它不起作用,我收到以下错误:

System.Runtime.InteropServices.MarshalDirectiveException: Cannot marshal 'parameter #6': Invalid managed/unmanaged type combination (this value type must be paired with Struct).


有什么想法我做错了吗?

最佳答案

尝试将参数#6更改为

static extern IntPtr CreateDesktop(..., [In] ref SECURITY_ATTRIBUTES lpsa);


(这会编译,并且在运行时不会引发异常,但是我仅使用伪参数对其进行了测试。)

CreateDesktop的C ++声明进行比较:

HDESK WINAPI CreateDesktop(..., __in_opt LPSECURITY_ATTRIBUTES lpsa);
                                  ↑      ↑ ↑
                                  [In] ref SECURITY_ATTRIBUTES lpsa


LP代表“长指针”,即LPSECURITY_ATTRIBUTES是指向SECURITY_ATTRIBUTES结构的指针。因此,在C#中,您需要通过引用传递您的struct实例(值类型)。

08-05 07:29