我正在尝试切换到另一个弹出窗口,但是出现了某种错误。我无法弄清楚为什么代码无法用于切换窗口
它给的错误是
java.lang.NullPointerException:条目中的空值:name = null
这是代码...
String parentWindowHandle = driver.getWindowHandle();
System.out.println("parentWindowHandle......"+parentWindowHandle);
//click on "register"
Actions act = new Actions(driver);
act.click(driver.findElement(By.id("ctl00_ContentPlaceHolder1_btnRegisterMe")));
act.perform();
sleep(26000);
String popUpWindowHandle=null;
Set<String> openWindowsList = driver.getWindowHandles();
for (String windowHandle : openWindowsList) {
System.out.println("windowHandle......"+windowHandle);
if (!windowHandle.equals(parentWindowHandle))
{popUpWindowHandle = windowHandle;
break;}
}
// Switching control to newly opened window
driver.switchTo().window(popUpWindowHandle);
最佳答案
如果您能够打印窗口句柄,请尝试
if (!windowHandle.equalsIgnoreCase(parentWindowHandle)){
popUpWindowHandle = windowHandle;
break;
}
代替
if(!windowHandle.equals(parentWindowHandle)){}