我想这会管用的:

const x: &str = "10";            // declare a const
let x: i32 = x.parse().unwrap(); // reuse the same name for a let binding
assert_eq!(10, x);

但是:
error[E0308]: mismatched types
 --> src/main.rs:3:9
  |
3 |     let x: i32 = x.parse().unwrap(); // reuse the same name for a let binding
  |         ^ expected i32, found reference
  |
  = note: expected type `i32`
             found type `&'static str`

error[E0277]: the trait bound `{integer}: std::cmp::PartialEq<&str>` is not satisfied
 --> src/main.rs:4:5
  |
4 |     assert_eq!(10, x);
  |     ^^^^^^^^^^^^^^^^^^ can't compare `{integer}` with `&str`
  |
  = help: the trait `std::cmp::PartialEq<&str>` is not implemented for `{integer}`
  = note: this error originates in a macro outside of the current crate (in Nightly builds, run with -Z external-macro-backtrace for more info)

这是有效的:
const x: &str = "10";
let y: i32 = x.parse().unwrap();
assert_eq!(10, y);

这也是:
let x: &str = "10";
let x: i32 = x.parse().unwrap();
assert_eq!(10, x);

我是做了什么错事,还是不可能用相同的名字将现有的const绑定与let绑定?

最佳答案

我想我明白了。。。当我使用let SOME_CONST时,编译器认为我是模式匹配。
当我修复类型时:

const x: i32 = 10;
let x: i32 = x + 1;
assert_eq!(11, x);

我得到一个不同的错误:
error[E0005]: refutable pattern in local binding: `_` not covered
 --> src/main.rs:3:9
  |
3 |     let x: i32 = x + 1;
  |         ^ interpreted as a constant pattern, not new variable

好像我把程序中所有出现的x都取出来,并将它们扩展到常数10
let 10: i32 = 10 + 1;
assert_eq!(11, x);

08-05 06:15