java - 无法使用复合键保存实体

使用复合键时尝试保存实体时出现异常。这是我尝试保存到的异常，模型和存储库。有人可以帮忙吗？


  org.springframework.beans.TypeMismatchException：转换失败
  'org.CheckType _ $$ _ jvst96c_4'类型的属性值转换为必需的类型
  属性“ checkType”的“ int”；嵌套异常为
  java.lang.IllegalArgumentException：无法转换类型的值
  将'org.CheckType _ $$ _ jvst96c_4'设置为属性的必需类型'int'
  'checkType'：PropertyEditor
  [org.springframework.beans.propertyeditors.CustomNumberEditor]
  返回了类型'org.CheckType _ $$ _ jvst96c_4'的不合适的值

@Entity
public class CheckType {
    @Id
    private int id;

    @NotNull
    private String name;

    @OneToMany(mappedBy = "checkType")
    private List<ClientCheck> checks;
    //getters and setters
}

@Entity
public class Offer {
    @Id
    @Column(name = "offerid")
    private Integer offerId;
    //...
    @OneToMany(mappedBy = "offer")
    private List<ClientCheck> clientCheckList;

    //getters and setters
}

@Entity
@IdClass(ClientCheckId.class)
public class ClientCheck {
    @Id
    @ManyToOne
    @JoinColumn(name = "offer_id", referencedColumnName = "offerid")
    private Offer offer;

    @Id
    @ManyToOne
    @JoinColumn(name = "check_type_id", referencedColumnName = "id")
    private CheckType checkType;

    @Id
    private Date timestamp;

    private String result;
    //getters and setters
}

public class ClientCheckId implements Serializable {
    private int offer;
    private int checkType;
    private Date timestamp;

    //getters and setters
    //equals and hashCode
}

public interface ClientCheckRepo extends JpaRepository<ClientCheck, ClientCheckId> {
}

最佳答案

如果另一个实体是组合键的一部分，则必须在ID类中声明该实体，而不是在其ID中声明：

public class ClientCheckId implements Serializable {
    private int offer;
    private CheckType checkType;
    private Date timestamp;

    //getters and setters
    //equals and hashCode
}

如果您想了解Hibernate的工作方式，则该错误消息非常容易理解：org.CheckType_$$_jvst96c_4是类的增强版本，Hibernate试图通过反射将其分配给checkType的ClientCheckId字段，但由于类型不兼容而失败。